The main difference between series and parallel circuits is how components are connected. Components in series lie on one continuous path, so the same current passes through each component. Components in parallel are connected across the same two points, so they have the same potential difference across them while the current divides between branches.
This distinction determines how resistance, current, voltage and power behave. It is a central part of IB Physics B.5 Current and circuits, studied by both SL and HL students under the course first assessed in 2025, as confirmed by the official IB Physics subject brief. This article concentrates specifically on comparing resistor configurations; for the wider topic, including emf, internal resistance and resistivity, use IB Physics Electricity and Circuits Explained.
Series vs parallel circuits at a glance
| Quantity | Series circuit | Parallel circuit |
|---|---|---|
| Connection | Components are arranged on one continuous path | Components are connected in separate branches across the same two nodes |
| Current | Same through every component | Divides between branches |
| Potential difference | Divided among components | Same across every branch |
| Equivalent resistance | R_s = R_1 + R_2 + ... | 1/R_p = 1/R_1 + 1/R_2 + ... |
| Effect of adding a resistor | Total resistance increases | Total resistance decreases |
| Failure of one branch or component | Usually opens the entire circuit | Other branches can continue operating |
The most useful memory rule is therefore:
- Series: same current, voltages add.
- Parallel: same voltage, currents add.
These are not arbitrary rules. They follow from conservation of charge and conservation of energy.
What makes components series or parallel?
Two components are in series if the same current must pass through one and then the other, with no junction between them that allows charge to take another route. It is not enough for the components to appear next to each other in a diagram. The electrical connections, rather than the visual layout, determine the configuration.
Two components are in parallel if both ends of one component connect to the same two nodes as both ends of the other. Because corresponding ends have the same electric potential, the potential difference across each component is identical.
A useful way to inspect a difficult diagram is to mark its nodes. Any points joined entirely by ideal connecting wire belong to the same node and are treated as having the same potential. Components connected between the same pair of nodes are parallel, even if the drawing has been rotated or rearranged.
How current behaves in series and parallel circuits
Electric current is the rate at which charge passes a point:
I = Δq/Δt
Its SI unit is the ampere (A). The official NIST explanation of electrical SI units also identifies the volt as the unit of potential difference and the ohm as the unit of resistance.
Current in a series circuit
In a series path, charge has only one route. If a current of 2.0 A enters a resistor, 2.0 A must leave it in steady-state operation; charge does not continuously accumulate inside the component. Consequently,
I = I_1 = I_2 = I_3 = ...
This is an application of conservation of charge. It is incorrect to say that current is gradually “used up” by successive components. Components transfer energy from the moving charges, but the rate of charge flow remains the same around a single series loop.
Current in a parallel circuit
At a junction, current divides among the available branches. The total current entering the junction equals the total current leaving it:
I_total = I_1 + I_2 + I_3 + ...
This is often called Kirchhoff’s junction rule or current law. A branch with lower resistance carries more current when all branches have the same voltage, because I = V/R.
For two parallel resistors, the branch currents satisfy the current-divider relationship
I_1/I_2 = R_2/R_1
This inverse relationship matters in exam questions. The branch with twice the resistance carries half the current, provided both branches connect across the same potential difference.
How voltage behaves in series and parallel circuits
Potential difference is the energy transferred per unit charge:
V = W/q
A potential difference of 1 V corresponds to 1 J of energy transferred per coulomb of charge. Voltage is therefore not a substance flowing around the circuit. It compares the electrical potential at two points.
Voltage in a series circuit
The source voltage is divided among components in a series loop:
V_total = V_1 + V_2 + V_3 + ...
This follows from conservation of energy. As charge completes a loop, the energy supplied per coulomb by an ideal source equals the total energy transferred per coulomb by the components.
For ohmic resistors carrying the same current, V = IR means that the voltage divides in proportion to resistance:
V_1/V_2 = R_1/R_2
The larger series resistance therefore has the larger potential difference across it. This is the basis of the potential-divider relationship.
Voltage in a parallel circuit
Each parallel branch begins and ends at the same two nodes. The potential difference is therefore identical across every branch:
V_total = V_1 = V_2 = V_3 = ...
If two lamps are connected in parallel directly across an ideal 12 V supply, each lamp has 12 V across it. The voltage does not split merely because there are two branches. Instead, the source supplies a larger total current than it would supply to either branch alone.
For a fuller distinction between voltage and current, see potential difference as energy per charge.
How resistance changes in series and parallel circuits
Resistance is defined by
R = V/I
The unit is the ohm (Ω), where 1 Ω = 1 V A⁻¹. The equation defines resistance at a particular operating point, while Ohm’s law states that current is proportional to potential difference for an ohmic conductor when relevant physical conditions, especially temperature, remain constant.
Equivalent resistance in series
For series resistors, current is common and the voltage drops add:
V = V_1 + V_2 + ...
Substituting V = IR gives
IR_s = IR_1 + IR_2 + ...
and therefore
R_s = R_1 + R_2 + ...
The equivalent resistance is always greater than any individual series resistance. Adding another resistor increases the opposition to the current, so the source current decreases if the supply voltage remains fixed.
Equivalent resistance in parallel
For parallel resistors, voltage is common and branch currents add:
I = I_1 + I_2 + ...
Using I = V/R gives
V/R_p = V/R_1 + V/R_2 + ...
and therefore
1/R_p = 1/R_1 + 1/R_2 + ...
For exactly two resistors, a useful shortcut is
R_p = (R_1R_2)/(R_1 + R_2)
The equivalent resistance of a parallel group must be less than its smallest branch resistance. Adding a branch creates another route for charge, increasing the total current for a fixed voltage and therefore reducing R_p = V/I. This result is also derived in the authoritative OpenStax treatment of series and parallel resistors.
For targeted background, review the RevisionDojo notes on resistance and resistivity and how resistance affects current.
Worked comparison using the same resistors
Consider an ideal 12 V supply and two resistors, R_1 = 4.0 Ω and R_2 = 8.0 Ω. Comparing the same components in both arrangements makes the consequences of rewiring clear.
Resistors connected in series
First find the equivalent resistance:
R_s = 4.0 + 8.0 = 12 Ω
The total current is
I = V/R_s = 12/12 = 1.0 A
Because this is a series circuit, both resistors carry 1.0 A. Their voltage drops are
V_1 = IR_1 = 1.0 × 4.0 = 4.0 VV_2 = IR_2 = 1.0 × 8.0 = 8.0 V
The check is 4.0 V + 8.0 V = 12 V. The larger resistance receives the larger share of the supply voltage.
Resistors connected in parallel
The equivalent resistance becomes
R_p = (4.0 × 8.0)/(4.0 + 8.0) = 2.67 Ω
Each resistor has the full 12 V across it. The branch currents are
I_1 = 12/4.0 = 3.0 AI_2 = 12/8.0 = 1.5 A
The total current is 3.0 + 1.5 = 4.5 A, which also agrees with I = 12/2.67 ≈ 4.5 A. Notice that the lower-resistance branch carries the greater current, while both branches have the same voltage.
Power in series vs parallel circuits
Electrical power is the rate of energy transfer:
P = IV = I²R = V²/R
The appropriate form depends on what is common. In series, current is common, so P = I²R immediately shows that the larger resistance dissipates more power. In parallel, voltage is common, so P = V²/R shows that the smaller resistance dissipates more power.
For the 12 V example, the total power in series is
P_series = VI = 12 × 1.0 = 12 W
In parallel it is
P_parallel = 12 × 4.5 = 54 W
The parallel arrangement draws more power because its equivalent resistance is lower. This comparison assumes an ideal source whose terminal voltage remains at 12 V; a real cell’s internal resistance can reduce terminal voltage when a large current is drawn.
Lamp brightness questions require care because filament lamps are not perfectly ohmic. Their resistance changes as the filament heats. Nevertheless, greater power dissipation generally corresponds to greater brightness, so the circuit rules remain the starting point for the analysis.
Measuring current and voltage correctly
An ammeter is connected in series with the component whose current is required. An ideal ammeter has zero resistance, so it does not significantly change the circuit current. Connecting it directly in parallel across a source could produce a dangerously large current in a real circuit.
A voltmeter is connected in parallel across the component. An ideal voltmeter has infinite resistance and draws no current. In practical instruments the resistance is very large rather than infinite, but IB calculations normally treat meters as ideal unless information states otherwise.
The connection rule follows the quantity being measured. Current describes charge passing through a component, so the ammeter must share its path; voltage compares the potential at two ends, so the voltmeter must bridge those points.
How to solve mixed series-parallel circuits
Many IB questions contain both arrangements. Use a systematic reduction rather than trying to apply one formula to the entire diagram:
- Mark the nodes and identify definite series or parallel groups.
- Calculate one equivalent resistance for the innermost group.
- Redraw the simplified circuit if the layout is difficult to follow.
- Repeat until one total external resistance remains.
- Use
I_total = V/R_totalto find the source current. - Work backwards through the original circuit, applying same-current and same-voltage rules.
- Check that currents balance at every junction and potential differences balance around each loop.
Do not treat two resistors as series if a branching junction lies between them. Similarly, two resistors are not necessarily parallel because they are drawn side by side; they must connect between the same pair of nodes.
The RevisionDojo B.5 Current and circuits notes provide the wider syllabus context, while the focused power and resistor configurations notes reinforce these calculations.
Common IB exam mistakes
Assuming current is consumed
Current is not used up as it travels through a resistor. Energy is transferred, but charge is conserved. In a single series path, the current after a component equals the current before it.
Dividing voltage equally in every series circuit
Series voltage divides equally only when the resistances are equal. In general, V_i = IR_i, so the largest resistance has the largest voltage drop.
Dividing current equally in every parallel circuit
Parallel branches carry equal currents only when their resistances are equal and they share the same voltage. Otherwise, lower resistance produces higher branch current.
Adding parallel resistances directly
Direct addition applies only to series resistors. For parallel resistors, add reciprocals and then take the reciprocal of the result. An answer larger than the smallest parallel resistance is an immediate warning that the calculation is wrong.
Using a two-resistor shortcut for three resistors
The product-over-sum expression applies directly to two parallel resistors. For three or more, use the reciprocal formula or combine two at a time.
Ignoring what is held constant
Adding a parallel branch reduces equivalent resistance and increases total current only when the source voltage remains fixed. Statements about how current or power changes should identify the assumed constant quantity.
Exam-focused revision strategy
Start each circuit question by writing the two structural rules beside the diagram: same current in series and same voltage in parallel. Then choose equations based on those known common quantities rather than selecting a formula from memory without considering the connections.
Estimate before calculating. A series equivalent resistance must exceed every member of the group, while a parallel equivalent must be smaller than the smallest member. In a parallel network, branch currents must add to the total; around a complete loop, the directed potential changes must sum to zero.
After learning the method, practise identifying configurations in unfamiliar diagrams. The IB Physics B.5 Questionbank is useful for targeted circuit calculations, and Jojo AI can help diagnose why a particular branch current or voltage is incorrect rather than simply supplying another formula.
Conclusion
In a series circuit, every component carries the same current, the voltage is shared, and resistances add directly. In a parallel circuit, every branch has the same voltage, current divides at junctions, and the reciprocal resistances add. Adding resistance in series raises equivalent resistance, while adding a parallel branch lowers it.
Successful IB circuit analysis depends on identifying the connections before calculating. Use conservation checks, resistance bounds and correct meter placement to catch errors. RevisionDojo’s B.5 Study Notes, Questionbank and Jojo AI are most useful when combined: review the rule, attempt an exam-style problem, and then examine any mistake in the reasoning.
Sources and referenced URLs
- Official IB Physics subject brief, first assessment 2025
- NIST SI units for electric current, voltage and resistance
- OpenStax: Resistors in Series and Parallel
- RevisionDojo: IB Physics Electricity and Circuits Explained
- RevisionDojo: B.5 Current and Circuits Notes
- RevisionDojo: B.5 Current and Circuits Questionbank
- RevisionDojo: B.5.4 Power and Resistor Configurations Notes
- RevisionDojo: B.5.3 Resistance and Resistivity Notes
- RevisionDojo: How Resistance Affects Current
- RevisionDojo: Potential Difference as Energy per Charge





