You prove geometric properties by representing points with position vectors, translating the required property into a vector relationship, and then establishing that relationship algebraically. This is Mathematics AA HL content from AHL 3.12: Vector definitions, applicable across Papers 1, 2 and 3.
The vector method
Let the position vectors of points and be and . Their displacement vector is
Once displacement vectors have been formed, use the condition corresponding to the property being proved.
| Geometric property | Vector condition |
|---|---|
| Parallel lines | for some scalar |
Worked proof: diagonals of a parallelogram
Suppose is a parallelogram with position vectors . Since opposite sides are equal as vectors,
Therefore,
so
The midpoint of diagonal has position vector
The midpoint of diagonal also has position vector . Hence the diagonals have the same midpoint, so they bisect each other.
Short example: proving collinearity
Let , , and have position vectors , , and . If
then . Therefore, both displacement vectors have the same direction and share the point , so , , and are collinear. The scalar multiple is the crucial evidence; merely obtaining three related coordinates is not a proof.
This method also distinguishes collinearity from equality of vectors. A negative scalar still proves collinearity but shows that the vectors point in opposite directions.
A common misconception is that a diagram demonstrates the result. It does not: a diagram suggests a property, while a vector equality proves it.
Exam technique
For the command term prove, show a complete logical sequence: define vectors, form the relevant displacement vectors, establish the required vector condition, and finish with an explicit geometric conclusion. Do not stop at an unexplained algebraic equality.
