A Maclaurin series represents a function as an infinite polynomial centred at . To approximate a function, truncate this series after a finite number of terms and substitute the required value of .
The Reasoning and Method
Provided the series converges to the function, its Maclaurin expansion is
Each coefficient is determined by a derivative evaluated at . A finite polynomial formed from the first terms is called a truncated Maclaurin series or Maclaurin polynomial.
To construct a series directly, evaluate , , and successive derivatives at zero. Then place each result over (n!) as the coefficient of . This works because matching these coefficients makes the polynomial have the same value and successive derivatives as at the centre. The degree of the truncation is the highest power retained.
| Function | Maclaurin series |
|---|---|
When using a known expansion, transform the variable carefully before substituting a numerical value. Replacing with in the exponential series changes every power: . State the highest power retained so the examiner can identify exactly where truncation occurred.
For example, approximate using terms up to and including :
Thus . The actual value is approximately , so the truncated series gives a close approximation. Accuracy is generally better when is closer to zero or when more terms are retained.
A common misconception is that every Maclaurin series equals its function everywhere. This is false: equality requires convergence to the function, while a truncation is normally only an approximation.
IB Exam Technique
This is IB Mathematics AA HL, AHL 5.19. On Paper 1, show the substitution or coefficient derivation exactly; on Papers 2 and 3, technology may check the approximation, but working is still required. If asked to show an expansion, calculate the necessary derivatives or obtain it from a known series using substitution, multiplication, differentiation, or integration.
