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How Does Nitration of Benzene Work? (HL)

Benzene undergoes nitration by electrophilic substitution: a hydrogen atom on the ring is replaced by a nitro group, NO2\text{NO}_2NO2​. Concentrated nitric acid provides the nitro group, while concentrated sulfuric acid generates the electrophile and acts as a catalyst.

This is Additional Higher Level (AHL) content in Reactivity 3.4, electron-pair sharing reactions.

Overall Reaction

The overall equation is:

C6H6(l)+HNO3(l)→C6H5NO2(l)+H2O(l)\text{C}_6\text{H}_6(l) + \text{HNO}_3(l) \rightarrow \text{C}_6\text{H}_5\text{NO}_2(l) + \text{H}_2\text{O}(l)C6​H6​(l)+HNO3​(l)→C

The mixture is usually warmed to approximately 505050 to 55 ∘C55\,^{\circ}\text{C}55∘C. Higher temperatures increase the likelihood of further substitution.

The Mechanism

  1. Formation of the electrophile: Concentrated sulfuric acid protonates nitric acid. The protonated nitric acid then loses water, producing the nitronium ion, NO2+\text{NO}_2^+NO2+​. At this stage, sulfuric acid behaves as a Brønsted and Lowry acid and nitric acid as a base. Protonation converts an OH group into water, a much better leaving group, allowing the electron-deficient nitronium ion to form. The ring temporarily loses aromatic stabilization, making the sigma complex relatively high in energy. Regeneration of sulfuric acid confirms its catalytic role.

  2. Electrophilic attack: Benzene’s delocalized π\piπ electrons attract NO2+\text{NO}_2^+. A curly arrow must begin at a bond and point to the nitrogen atom of . A carbon bonded to nitrogen bond forms, temporarily disrupting the delocalized electron system and producing a positively charged . Its positive charge is delocalized around the ring.

A common misconception is that nitration is an addition reaction. It is substitution because loss of H+\text{H}^+H+ restores the stable delocalized electron system of benzene.

Exam Technique

For an explain or mechanism question, identify NO2+\text{NO}_2^+NO2+​ as the electrophile, show both curly arrows starting from electron pairs, include the sigma complex, and state that aromaticity is restored. Do not draw a curly arrow starting from the electrophile.

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6
​
H5​
NO2​
(
l
)
+
H2​O(l)
NO
2+​
π\piπ
NO2+\text{NO}_2^+NO2+​
sigma complex
  • Restoration of aromaticity: The hydrogensulfate ion removes the proton attached to the carbon bonded to NO2\text{NO}_2NO2​. A curly arrow moves from the carbon bonded to hydrogen bond back into the ring, reforming the π\piπ system. Nitrobenzene forms, and sulfuric acid is regenerated.

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