For both SL and HL, calculate the force using , where is the angle between the conventional current and the magnetic field. Substitute values in SI units, then determine the force direction using a hand rule.
The Reasoning and Mechanism
A current consists of moving charge carriers. In a magnetic field, these carriers experience a magnetic force, and this force is transferred to the wire. For a straight wire in a uniform field, the force magnitude is
where:
- is the magnetic force in newtons (N)
- is magnetic field strength in teslas (T)
- is conventional current in amperes (A)
- is the length of wire inside the field in metres (m)
- is the angle between the current and magnetic field
The factor accounts for the component of the wire perpendicular to the field.
At the microscopic level, each mobile charge experiences . Adding the forces on all charge carriers in the field gives the macroscopic wire equation. Only the wire length actually within the uniform magnetic field is used for ; do not use the wire’s total length unless all of it lies in the field.
| Orientation | Force |
|---|---|
| Current perpendicular to field, | Maximum: |
| Current at an intermediate angle |
For example, if , , , and :
The force acts perpendicular to both the current and magnetic field. Use the prescribed hand rule with the direction of conventional current, not electron flow. Reversing either the current or the field reverses the force; reversing both leaves the force direction unchanged.
Exam Technique
For a Calculate question, show the equation, substitution, and final value. A common misconception is measuring between the force and field; it must be measured between the conventional current and the magnetic field. In direction questions, state clearly that the force is perpendicular to both. A labelled direction or hand-rule statement may also be required.
