Proof by contradiction feels difficult because you must temporarily work from a statement you ultimately intend to reject. That reverses the usual direction of mathematical reasoning: instead of beginning with accepted facts and moving directly towards the result, you assume the result is false, derive an impossibility, and then return to the original claim.
For proof by contradiction in IB Maths, clarity depends on four visible stages: state the claim's correct negation, reason from that assumption, identify a genuine contradiction, and explicitly conclude that the original claim is true. Most weak solutions fail not because the algebra is difficult, but because one of these logical transitions remains unstated.
What proof by contradiction actually proves
Suppose the statement you want to establish is called P. A proof by contradiction has the logical form:
- Assume that P is false, so not P is true.
- Use not P, together with established facts and definitions, to derive a contradiction.
- Conclude that not P cannot be true.
- Therefore, P must be true.
Symbolically, the central chain is:
not P ⇒ contradiction, and therefore P.
A contradiction may be an impossible equality, such as 0 = 1, or two incompatible conclusions, such as an integer being both odd and even. It can also conflict directly with an assumption, such as proving that two supposedly coprime integers share a factor.
The contradiction does not mean that mathematics has broken down. It shows that the temporary assumption introduced at the beginning cannot be maintained.
According to the current published IB Mathematics: Analysis and Approaches guide, simple deductive proof appears at standard level, while proof by contradiction, mathematical induction, and proof by counterexample are included in the additional higher level content. The guide lists examples including irrationality proofs, Euclid's proof that infinitely many primes exist, and results involving rational and irrational numbers.
Why is proof by contradiction so hard to structure clearly?
The method combines several reasoning tasks that students often try to perform simultaneously. You must interpret the claim, negate it accurately, predict what impossibility might emerge, and then present the argument in a forward logical order.
You discover the proof backwards but write it forwards
While solving a contradiction problem, you often begin by asking, “What contradiction would finish this proof?” You may then work backwards to determine which algebraic result would produce it.
The final proof must be written in the opposite direction. It should begin with the negated claim and move forwards through justified consequences. A page containing exploratory calculations may reveal the right idea, but it is not automatically a clear proof.
This creates a useful distinction:
| During discovery | In the final proof |
|---|---|
| Guess a likely contradiction | State the negated claim |
| Work backwards towards a useful equation | Derive each consequence forwards |
| Test several possible approaches | Keep only the successful chain |
| Use informal notes and abbreviations | Explain why each implication follows |
| Recognize that the argument works | State precisely what has been contradicted |
Strong proof writing therefore requires a rewrite stage. Do not expect your first attempt to have the structure of your final answer.
Negating a statement is more difficult than writing “the opposite”
A contradiction proof begins with the logical negation of the complete claim. Informal opposites are often inaccurate.
Consider the statement:
If n² is even, then n is even.
Its negation is not “n² is odd and n is odd.” A conditional statement “if A, then B” is false precisely when A is true and B is false. The correct contradiction assumption is therefore:
n² is even and n is odd.
Quantifiers also change under negation:
| Original statement | Correct negation |
|---|---|
| Every integer has property P | At least one integer does not have property P |
| No integer has property P | At least one integer has property P |
| There exists an integer with property P | No integer has property P |
| If A, then B | A is true and B is false |
Many supposed algebra errors in IB Maths AA proof questions are actually negation errors made before the algebra begins.
The false assumption must still be used consistently
Students sometimes hesitate because they know the contradiction assumption is false. However, you must treat it as temporarily valid and examine its consequences.
You may combine that assumption with definitions, earlier results, and facts given in the question. You may not insert another unsupported claim merely because you expect the argument to end impossibly. Every intermediate step must remain logically valid.
The contradiction may be mathematically visible but rhetorically hidden
Suppose your work shows that p and q are both even after initially defining them to have no common factor. That is a contradiction, but the reader should not have to reconstruct it.
Write the conflict explicitly:
Therefore, 2 divides both p and q. This contradicts the assumption that p and q have no common factor.
The phrase “this is a contradiction” is not sufficient unless the conflicting statements are clear from the surrounding work. A well-written proof names both sides of the conflict.
Students often stop one sentence too early
Finding an impossible result only rejects the contradiction assumption. The proof still needs to reconnect that rejection to the original claim.
A complete ending is:
Hence the assumption that √3 is rational is false. Therefore, √3 is irrational.
That final sentence may appear obvious, but it closes the logical loop and makes the proof self-contained.
A clear proof by contradiction template
The following template works for most IB Maths AA contradiction questions.
Step 1: Announce the method
Write:
We prove the result by contradiction.
This tells the examiner that the apparently incorrect assumption in the next line is deliberate.
Step 2: State the exact negation
Write:
Assume, for contradiction, that [precise negation of the claim].
If the original result is conditional, retain the hypothesis and negate the conclusion. If it contains “for every” or “there exists,” change the quantifier correctly.
Step 3: Translate definitions into usable mathematics
For example:
- If n is odd, write n = 2k + 1 for some integer k.
- If x is rational, write x = p/q, where p and q are integers, q ≠ 0, and the fraction is in lowest terms.
- If a smallest positive value exists, give it a name and use its defining property.
This is often the bridge between the verbal assumption and the algebra.
Step 4: Build a justified implication chain
Each line should follow from the assumption, a definition, an established theorem, or valid algebra. Include short explanations when the implication is not immediately visible.
Step 5: Identify the contradiction precisely
Use a sentence of the form:
This says that [result A], but [assumption or established fact B]. These statements are incompatible.
Step 6: Close the proof
Write:
Therefore, the contradiction assumption is false, so [original claim] is true.
This six-stage structure is more reliable than memorizing a particular irrationality proof because it transfers to divisibility, non-existence, uniqueness, and number-theory questions.
Proof by contradiction example: an even square
Claim: If n² is even, then n is even.
We prove the result by contradiction. Assume that n² is even but n is not even. Since n is an integer, n must therefore be odd, so n = 2k + 1 for some integer k.
Then
n² = (2k + 1)² = 4k² + 4k + 1 = 2(2k² + 2k) + 1.
Because 2k² + 2k is an integer, this expression shows that n² is odd. However, the contradiction assumption stated that n² is even. Thus n² would have to be both even and odd, which is impossible.
Therefore, the assumption that n is not even is false. Hence, if n² is even, n is even.
Notice the structural features:
- The negation preserves “n² is even” and changes “n is even” to “n is not even.”
- The definition of an odd integer produces the algebraic form needed.
- The contradiction is explicitly named.
- The final line restates the original conditional claim.
Proof by contradiction example: √3 is irrational
Claim: √3 is irrational.
Assume, for contradiction, that √3 is rational. It can then be written as
√3 = p/q,
where p and q are integers, q ≠ 0, and p/q is in lowest terms. Squaring and rearranging gives
3q² = p².
Therefore, 3 divides p². Since 3 is prime, this implies that 3 divides p, so write p = 3k for some integer k. Substitution gives
3q² = 9k², and hence q² = 3k².
It follows that 3 divides q² and therefore 3 divides q. Thus 3 divides both p and q, contradicting the original choice of p/q in lowest terms.
The assumption that √3 is rational must therefore be false. Hence, √3 is irrational.
This proof illustrates an important writing principle: state the lowest-terms condition at the beginning. Without it, showing that p and q share a factor does not contradict anything. The University of Toronto's proof by contradiction note uses the same essential structure for √2.
How to plan a contradiction proof before writing it
A short planning routine prevents most structural errors.
- Rewrite the target as a precise statement. Identify any conditional language or quantifiers.
- Write its negation separately. Check that you have negated the whole claim rather than one convenient phrase.
- List possible contradictions. Look for parity conflicts, a shared factor, violation of an inequality, or conflict with minimality.
- Choose a definition that creates algebra. Rational numbers become fractions; odd integers become 2k + 1.
- Find a forward chain. Confirm that every line follows from something already established.
- Rewrite cleanly. Remove unsuccessful attempts and make the contradiction explicit.
The UBC structure of a proof by contradiction similarly emphasizes announcing the method, assuming the negation, forming a chain of implications, and concluding that the original statement holds.
Contradiction compared with other proof methods
Proof by contradiction is not automatically the best method whenever a question uses the word “prove.”
| Method | Starting point | Appropriate use |
|---|---|---|
| Direct proof | Given assumptions | A natural sequence of deductions reaches the conclusion |
| Contrapositive | Assume the conclusion is false | “If A, then B” is easier to prove as “if not B, then not A” |
| Contradiction | Assume the complete claim is false | The negation creates a useful object or impossible condition |
| Counterexample | Find one case where a universal claim fails | Disproving “for every” or “always” statements |
| Induction | Establish a base case and inductive step | Claims indexed over consecutive integers |
A contrapositive proof and a contradiction proof can look similar. To prove “if A, then B” by contrapositive, you assume not B and directly establish not A. In a contradiction proof, you assume A and not B together, then derive an impossibility.
Do not call a counterexample a contradiction proof. One valid counterexample disproves a universal statement; contradiction establishes that an assumed negation cannot hold.
For broader syllabus context without duplicating every proof method here, see IB Maths AA Number and Algebra Explained for Exams. The dedicated AHL 1.15 proof notes compare contradiction with induction and counterexample in more detail.
Common exam mistakes and how to correct them
Assuming the original claim
If the goal is to prove that √3 is irrational, beginning with “assume √3 is irrational” proves nothing. Assume the negation, which is that √3 is rational.
Using examples instead of a general argument
Checking n = 2, 4, and 6 cannot prove a statement about every even integer. A proof must work for an arbitrary integer satisfying the stated conditions.
Omitting conditions from definitions
When writing a rational number as p/q, include q ≠ 0. If the intended contradiction concerns common factors, specify that p/q is in lowest terms.
Reaching a surprising result rather than an impossible one
A negative value, awkward fraction, or unexpected answer is not automatically contradictory. You need a result that conflicts with a definition, assumption, theorem, or established fact.
Using the conclusion inside the reasoning
This is circular reasoning. Every intermediate statement must follow from the contradiction assumption and independent mathematical facts, not from the result being proved.
Writing unexplained implication jumps
In the √3 proof, “3 divides p², so 3 divides p” requires a known prime-divisibility result. If the fact is central and not obvious in context, briefly justify or name it.
Forgetting the conclusion
Always state that the assumption is false and the original claim follows. This separates an unfinished calculation from a complete mathematical argument.
How to practise proof writing for IB exams
Proof improves through writing, checking, and rewriting rather than passive reading. After completing a question, label the four essential components in your answer: negation, deduction, contradiction, and conclusion.
RevisionDojo's AHL 1.15 Questionbank provides targeted contradiction, induction, and counterexample practice. The associated proof flashcards are useful for definitions and logical structures, while the Number and Algebra videos include worked contradiction examples.
When reviewing a written solution with Jojo AI, ask specifically whether you negated the claim correctly, used every assumption, and identified the contradiction explicitly. Those questions produce more useful feedback than asking only whether the final answer is correct. You can then use the broader IB Mathematics AA Questionbank to mix proof with other Number and Algebra skills under timed conditions.
Conclusion
Proof by contradiction is hard to structure because the method separates how a proof is discovered from how it must be presented. You often search backwards for an impossibility, but the finished argument must move forwards from the exact negation of the claim.
A reliable IB Maths AA proof states the method, writes the negation precisely, translates definitions into algebra, derives a genuine conflict, and closes the logical loop. RevisionDojo's AHL 1.15 notes, Questionbank, videos, and Jojo AI feedback can help you practise that structure until each stage becomes deliberate rather than implicit.
Sources and referenced URLs
- IB Mathematics: Analysis and Approaches guide
- University of Toronto proof by contradiction note
- UBC structure of a proof by contradiction
- IB Maths AA Number and Algebra Explained for Exams
- RevisionDojo AHL 1.15 proof topic
- RevisionDojo AHL 1.15 proof notes
- RevisionDojo AHL 1.15 Questionbank
- RevisionDojo AHL 1.15 flashcards
- RevisionDojo Number and Algebra videos
- RevisionDojo IB Mathematics AA Questionbank




