- IB
- AHL 1.15—Proof by induction, contradiction, counterexamples
Practice AHL 1.15—Proof by induction, contradiction, counterexamples with authentic IB Mathematics Analysis and Approaches (AA) exam questions for both SL and HL students. This question bank mirrors Paper 1, 2, 3 structure, covering key topics like functions and equations, calculus, complex numbers, sequences and series, and probability and statistics. Get instant solutions, detailed explanations, and build exam confidence with questions in the style of IB examiners.
Disprove the following statement by providing a counterexample:
"For any integers , , and , if divides and divides , then divides ."
Prove by contradiction that if the square of an integer is an even number, then the integer itself must be an even number.
Prove by induction that , for , .
Disprove the following statement by providing a counterexample: "For any square matrices and of the same size, ."
Given equation .
Prove by induction that the given equation is divisible by for all positive integers .
Prove by induction that if , , then . Hence deduce that if , , then .
Prove by contradiction that the equation has no integer roots.
Prove by mathematical induction that for .
Hence or otherwise, determine the Maclaurin series of in ascending powers of , up to and including the term in
Consider the following trigonmetric expression
Show that the expression equal to
Hence, using mathematical induction and the above identity, prove that for .
Consider the sequence defined by for all positive integers .
Using proof by mathematical induction, prove that for all integers .