Differentiate the function and solve . The resulting -values are where the curve has zero gradient, called stationary points.
A zero derivative means the tangent is horizontal at that input. However, the curve may turn, or it may continue increasing or decreasing through a stationary point of inflexion.
This is part of SL 5.6, Stationary points, local maximum and minimum points, studied by both SL and HL Mathematics: Applications and Interpretation students.
Method
For a curve :
- Find the derivative (f'(x)), which represents the gradient of the curve.
- Set the gradient equal to zero:
- Solve this equation, algebraically or using a graphic display calculator (GDC).
- Substitute each solution into to obtain the coordinates of the stationary points.
- Check how the sign of (f'(x)) changes around each point.
Worked Example
Let
Differentiate:
Set the derivative equal to zero:
Therefore, or . Substitution gives and , so the stationary points are and .
| Change in (f'(x)) | Classification |
|---|---|
| Positive to negative, | Local maximum |
| Negative to positive, | Local minimum |
| No sign change | Neither maximum nor minimum |
Here, (f'(x)) changes from positive to negative at , so is a local maximum. It changes from negative to positive at , so is a local minimum.
For this example, testing one value in each interval , , and gives derivative signs , (-), and , respectively. This confirms both classifications.
On a restricted domain, also check the endpoints when finding the greatest or least value. A local stationary point is not necessarily the global maximum or minimum.
Exam Technique
A common misconception is that every solution of is a maximum or minimum. It is only guaranteed to be a stationary point; classification requires a sign check or inspection of the graph. In AI Paper 1 or Paper 2, show the equation before giving GDC solutions, retain full calculator precision, and state coordinates rather than only the -values when points are requested.
