Use Euler's method by starting from a known point and repeatedly moving forward using the gradient supplied by the differential equation. For step size , apply and ; each new point becomes the starting point for the next step.
This is AHL 5.16, so it is IB Mathematics: Applications and Interpretation HL-only content. The example has a short-response Paper 1 style, but Euler's method may appear on any HL paper; a GDC is available throughout.
Suppose , , and estimate using . Here, , with . The is
| Step | Current point | Gradient | Updated value |
|---|---|---|---|
The corresponding updates are and . Therefore, .
Geometrically, the method replaces the solution curve on each interval with a short tangent-line segment. At the current point, the differential equation gives the tangent gradient, so estimates the vertical change. This explains why every gradient must be evaluated before either coordinate is updated.
Euler's method gives a numerical approximation, not an exact solution. A smaller generally improves accuracy because the tangent better matches the curve over a shorter interval, although more iterations are required. For repeated calculations, enter the two recurrences into a spreadsheet or GDC table and retain full precision.
A common misconception is to calculate the next gradient using partially updated coordinates. Instead, evaluate using both current coordinates first. Another error is performing the wrong number of steps: calculate .
Before calculating, determine the number of iterations and organize the values consistently. A table with columns for , , , , and reduces substitution errors. Check that the final -value equals the requested target before reporting the corresponding approximate -value in context.
Exam technique: Write both recurrence equations and show the first iteration explicitly, since this provides evidence for the method mark. Round only the final answer and use because Euler's method is approximate.
