For both SL and HL IB Physics, calculate the period using , where is the total oscillating mass in kilograms and is the spring constant in . The resulting period is measured in seconds.
This equation belongs to simple harmonic motion in subtopic C.1. It applies when the restoring force follows Hooke's law, , the oscillations are small, damping is negligible, and the spring's mass is negligible or included in an effective oscillating mass.
Why the Formula Works
Hooke's law gives a restoring force directed opposite to the displacement. Combining with gives
The defining equation of simple harmonic motion is . Therefore,
Since , substitution gives
The square-root relationship means that period does not change in direct proportion to either mass or spring constant.
Worked Example
A mass is attached to a spring with :
The system therefore completes one oscillation every .
| Change | Effect on the period |
|---|---|
| Increase | Period increases because |
| Increase |
A common misconception is that doubling the mass doubles the period. Doubling actually multiplies by , while quadrupling doubles .
Experimentally, can be determined from the gradient of a force-extension graph. Repeated timing of several oscillations reduces percentage uncertainty: divide the total measured time by the number of oscillations.
For data analysis, square the relationship and plot period squared against oscillating mass. The model predicts a straight line through the origin. Its gradient equals four pi squared divided by the spring constant, so the spring constant can be determined from the gradient. A non-zero intercept may indicate unaccounted spring mass or systematic error.
Exam Technique
For a Calculate question, show the equation, substitution, and final value. Use SI units, select mass rather than weight, and never insert into the mass-spring period formula.
