You find the area under a curve by evaluating the definite integral of its function between the stated limits. If on ([a,b]), then the geometric area is .
The Reasoning
A definite integral accumulates infinitely thin vertical strips across an interval. Geometrically, it represents the signed area between , the -axis, and the lines and . Area above the axis is positive; area below it is negative.
This is IB Mathematics: Applications and Interpretation SL 5.5. At SL, examination questions on area under a curve use , so the integral directly equals the geometric area. A GDC is available on every Math AI paper.
For example, find the area under from to :
Using the power rule,
Apply the upper and lower limits:
Therefore, the area is square units. The constant is not included in the final evaluation because it cancels when the endpoint values are subtracted.
A common misconception is that every definite integral automatically gives geometric area. It gives signed area. If a curve crosses the axis, negative contributions can cancel positive ones; finding total geometric area would require splitting the interval at the roots and making each contribution positive. That extension is beyond the specific SL 5.5 case described here.
Exam Technique
- State the boundaries and write the integral before evaluating it.
- Use your GDC to evaluate the definite integral, but show the mathematical set-up rather than calculator keystrokes.
- Keep full precision until the end, then give an exact answer or round to three significant figures unless instructed otherwise.
- Include square units when the variables have physical units.
The command term calculate requires relevant working. The integral set-up can earn the method mark even if a later numerical error occurs.
