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    HLPaper 2

    A particle moves along a horizontal path such that at time ttt seconds, t≥0t \geq 0t≥0, its acceleration aaa is given by a=2t−1a = 2t - 1a=2t−1. When t=6t = 6t=6, its displacement sss from a fixed point P is 18.25 m. When t=15t = 15t=15, its displacement from P is 922.75 m. Find an expression for sss in terms of ttt.

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