Introduction
Integration by Parts is one of the most important integration techniques tested on the AP Calculus BC exam. While many students feel confident with u-substitution, Integration by Parts requires a different type of problem-solving skill. Understanding when and how to apply the method is key to solving advanced integrals, especially those involving products of functions like logarithms, exponentials, and trigonometric expressions.
In this guide, we’ll break down the Integration by Parts formula, show you step-by-step examples, highlight common mistakes, and provide study tips to ensure you’re ready for the AP Calculus BC exam.
What is Integration by Parts?
Integration by Parts is based on the product rule for differentiation but applied in reverse. It’s especially useful when the integral involves a product of two functions that can’t be solved with basic substitution.
The formula is:
∫u dv = uv – ∫v du
Where:
- u = the function you choose to differentiate
- dv = the function you choose to integrate
- du = derivative of u
- v = integral of dv
When to Use Integration by Parts
Students often ask, “How do I know when to use Integration by Parts?”
You should consider it when the integral involves:
- A product of polynomial and exponential functions (e.g., ∫x e^x dx)
- A product of polynomial and trigonometric functions (e.g., ∫x sin(x) dx)
- Logarithmic or inverse trig functions (e.g., ∫ln(x) dx, ∫arctan(x) dx)
The LIATE Rule for Choosing u
Choosing u correctly is the most important part of Integration by Parts. The LIATE rule helps:
