The nth term of an arithmetic progression is given by v_n = 15 - 3n.

Question

SLPaper 1

1.

State the value of the initial term, v_1.

[1]

Verified

Solution

$v_1=12$

2.

Given that the nth term of this progression is -33, find the value of n.

[2]

Verified

Solution

$15-3n=-33$ $n=16$

3.

Find the common difference, d.

[2]

Verified

Solution

valid approach to find d $v_2-v_1=9-12$ OR recognize gradient is -3 OR attempts to solve $-33=12+15d$ $d=-3$

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