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    The nth term of an arithmetic progression is given by $v_n = 15 - 3n$.

    Question
    SLPaper 1

    The nth term of an arithmetic progression is given by vn=15−3nv_n = 15 - 3nvn​=15−3n.

    1.

    State the value of the initial term, v1v_1v1​.

    [1]
    Verified
    Solution

    v1=12v_1=12v1​=12 A1

    2.

    Given that the nth term of this progression is -33, find the value of n.

    [2]
    Verified
    Solution

    15−3n=−3315-3n=-3315−3n=−33 M1

    n=16n=16n=16 A1

    3.

    Find the common difference, ddd.

    [2]
    Verified
    Solution

    valid approach to find ddd M1

    v2−v1=9−12v_2-v_1=9-12v2​−v1​=9−12 OR recognize gradient is -3 OR attempts to solve −33=12+15d-33=12+15d−33=12+15d M1

    d=−3d=-3d=−3 A1

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    SL 1.2—Arithmetic sequences and series

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