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    SLPaper 2

    A manufacturer produces packets of flour whose weights, in grams, can be modelled by a normal distribution with mean 100010001000 and standard deviation 3.53.53.5. A packet of flour is rejected for sale if its weight is less than 995995995 grams.

    1.

    Find the probability that a packet selected at random is rejected.

    [2]
    Verified
    Solution

    Note: In this question, do not penalise incorrect use of strict inequality signs. Let X=X=X= weight of a packet of flour

    evidence of identifying the correct area***(M1)*** P(X<995)=0.0765637...{P(X<995)=0.0765637...}P(X<995)=0.0765637... =0.0766{=0.0766}=0.0766A1

    [2 marks]

    2.

    Estimate the number of packets which will be rejected from a random sample of 100{100}100 packets.

    [1]
    Verified
    Solution

    Note: In this question, do not penalise incorrect use of strict inequality signs. Let XXX = weight of a packet of flour

    0.0766×1000.0766 \times 1000.0766×100 ≈8\approx 8≈8A1

    Note: Accept 7.66.

    [1 mark]

    3.

    Given that a packet is not rejected, find the probability that it has a weight greater than 1005{1005}1005 grams.

    [3]
    Verified
    Solution

    Note: In this question, do not penalise incorrect use of strict inequality signs. Let XXX = weight of a packet of flour

    recognition that P(X>1005)∩(X≥995)P(X > 1005) \cap (X \geq 995)P(X>1005)∩(X≥995) is required***(M1)*** P(X≥995)∩(X>1005)P(X≥995)\frac{{P(X \geq 995) \cap (X > 1005)}}{{P(X \geq 995)}}P(X≥995)P(X≥995)∩(X>1005)​ P(X>1005)P(X≥995)\frac{{P(X > 1005)}}{{P(X \geq 995)}}P(X≥995)P(X>1005)​(A1) 0.0765637…1−0.0765637…\frac{{0.0765637\ldots}}{{1 - 0.0765637\ldots}}1−0.0765637…0.0765637…​ =0.0765637…0.923436…= \frac{{0.0765637\ldots}}{{0.923436\ldots}}=0.923436…0.0765637…​ =0.0829= 0.0829=0.0829 A1

    [3 marks]

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