Practice SL 5.8—Trapezoid rule with authentic IB Mathematics Applications & Interpretation (AI) exam questions for both SL and HL students. This question bank mirrors Paper 1, 2, 3 structure, covering key topics like core principles, advanced applications, and practical problem-solving. Get instant solutions, detailed explanations, and build exam confidence with questions in the style of IB examiners.
A water tank's cross-sectional area, , in , varies with height , in meters. The volume is . Assume , with measurements:
| 0 | 2 | 4 | 6 | 8 | |
|---|---|---|---|---|---|
| 20 | 18 | 18 | 20 | 24 |
Use the trapezoidal rule with 4 intervals to estimate the volume.
Sketch the graph of and shade the region used in part (a).
Use the points to form a system of equations for . Solve for one coefficient.
Find the exact volume by integrating the quadratic model, assuming $A(h)=24- 0.5 h^{2}+h .
Calculate the percentage error of the trapezoidal estimate.
If water flows in at , estimate the filling time using the trapezoidal volume.
Explain how the number of intervals affects the trapezoidal rule's accuracy.
A structural engineer is designing a curved roof for a building. The height of the roof, , in meters, is modeled by , for , where is the horizontal distance from one end. The cross-sectional area under the roof is critical for ventilation calculations. The engineer takes measurements at specific points:
| (m) | 0 | 2 | 4 | 6 | 8 | 10 |
|---|---|---|---|---|---|---|
| (m) | 0 | 1.60 | 4.16 | 6.72 | 8.32 | 8.00 |
Find and determine the maximum height of the roof.
Use the trapezoidal rule with 5 intervals to estimate the cross-sectional area under the roof.
Sketch the graph of from to and shade the region corresponding to the estimate in Part 2.
Write down the integral representing the exact cross-sectional area and evaluate it.
Calculate the percentage error of the trapezoidal rule estimate compared to the exact area.
Explain why the trapezoidal rule estimate differs from the exact area, referencing the shape of the curve.
A roof's height, , in meters, is modeled by , for , where is the horizontal distance from one end in meters. The area under the curve represents the cross-sectional area of the roof space.
Find and determine the maximum height of the roof.
Use the trapezoidal rule with 4 intervals to estimate the cross-sectional area.
Compare the estimate from part 2 with the exact area found by integration.
A sculpture's height, , in meters, is modeled by a cubic function over a 9-meter base, where is the distance from one end in meters. The heights at specific distances are given in the following table:
| (m) | 0 | 3 | 6 | 9 |
|---|---|---|---|---|
| (m) | 1 | 2.5 | 3 | 2 |
Use the trapezoidal rule with 3 intervals to estimate the area under the curve.
Assume . Use the given points to find two linear equations in .
Sketch the graph of and shade the region used in part (a).
A transportation company is studying the velocity of a delivery vehicle over time, modeled by the function in meters per second, from to seconds.
Divide the interval into 4 equal sub-intervals. Write the values of at each endpoint.
Calculate the values of the function at each endpoint.
Use the trapezoidal rule with these values to approximate the total distance travelled by the particle.
Verify the result by calculating the exact integral of over the interval .
Compare the approximation with the exact answer and state which is larger. Explain why the difference might occur.
A renewable energy company is analyzing the growth of a new type of solar panel's instantaneous power output over time. The power output is modeled by the function (in kilowatts) over the interval years.
Divide the interval into 4 equal sub-intervals and write down the values of at each endpoint.
Use the trapezoidal rule with 4 sub-intervals to approximate the total energy produced (area under the curve ) from to .
Use your calculator to find the exact value of the total energy produced and compare it with the approximation from Part 2.
A scientist models the concentration of a chemical in a solution, , in , over 5 hours, using . The total amount of chemical is proportional to the area under the curve. Measurements are taken hourly:
| (h) | 0 | 1 | 2 | 3 | 4 | 5 |
|---|---|---|---|---|---|---|
| (mg/L) | 2 | 2.70 | 3.64 | 4.95 | 6.70 | 9.07 |
Use the trapezoidal rule with 5 intervals to estimate the total amount of chemical.
Show that .
Using part 2, explain how a linear regression on transformed data could confirm the model's parameters.
Find the exact total amount of chemical using integration.
Calculate the absolute error of the trapezoidal estimate.
Suggest one way to improve the trapezoidal rule estimate's accuracy.
A cylindrical container's radius, , in centimeters, varies with height , in centimeters, from the base. The volume of liquid it can hold is given by . The radii are measured at cm intervals as follows:
| (cm) | 0 | 1 | 2 | 3 | 4 | 5 |
|---|---|---|---|---|---|---|
| (cm) | 3 | 4 | 5 | 4 | 3 | 2 |
Use the trapezoidal rule with 5 intervals to estimate the volume of the container.
Sketch the graph of against and shade the region used to estimate the volume in part 1.
A city is planning to build a new park. The shape of the park is defined by the region bounded by the curve , the -axis, and the vertical line , where and are measured in kilometers.
Divide the interval into 4 equal sub-intervals and state the -values.
Calculate the value of at each endpoint.
Use the trapezoidal rule with these 4 sub-intervals to approximate the area of the park.
Calculate the exact area of the park by integrating from 0 to 2.
Compare the approximation with the exact value and explain the difference.
A designer models the height of an arch, , in meters, over a 10-meter span, where is the horizontal distance from the left support. The arch's height is given by , for . The area under the arch represents the space available for passage.
Use the trapezoidal rule with 5 intervals to estimate the area under the arch.
Sketch the graph of and shade the region corresponding to the estimate in Part 1.
Find the exact area under the arch using integration.
Practice SL 5.8—Trapezoid rule with authentic IB Mathematics Applications & Interpretation (AI) exam questions for both SL and HL students. This question bank mirrors Paper 1, 2, 3 structure, covering key topics like core principles, advanced applications, and practical problem-solving. Get instant solutions, detailed explanations, and build exam confidence with questions in the style of IB examiners.
A water tank's cross-sectional area, , in , varies with height , in meters. The volume is . Assume , with measurements:
| 0 | 2 | 4 | 6 | 8 | |
|---|---|---|---|---|---|
| 20 | 18 | 18 | 20 | 24 |
Use the trapezoidal rule with 4 intervals to estimate the volume.
Sketch the graph of and shade the region used in part (a).
Use the points to form a system of equations for . Solve for one coefficient.
Find the exact volume by integrating the quadratic model, assuming $A(h)=24- 0.5 h^{2}+h .
Calculate the percentage error of the trapezoidal estimate.
If water flows in at , estimate the filling time using the trapezoidal volume.
Explain how the number of intervals affects the trapezoidal rule's accuracy.
A structural engineer is designing a curved roof for a building. The height of the roof, , in meters, is modeled by , for , where is the horizontal distance from one end. The cross-sectional area under the roof is critical for ventilation calculations. The engineer takes measurements at specific points:
| (m) | 0 | 2 | 4 | 6 | 8 | 10 |
|---|---|---|---|---|---|---|
| (m) | 0 | 1.60 | 4.16 | 6.72 | 8.32 | 8.00 |
Find and determine the maximum height of the roof.
Use the trapezoidal rule with 5 intervals to estimate the cross-sectional area under the roof.
Sketch the graph of from to and shade the region corresponding to the estimate in Part 2.
Write down the integral representing the exact cross-sectional area and evaluate it.
Calculate the percentage error of the trapezoidal rule estimate compared to the exact area.
Explain why the trapezoidal rule estimate differs from the exact area, referencing the shape of the curve.
A roof's height, , in meters, is modeled by , for , where is the horizontal distance from one end in meters. The area under the curve represents the cross-sectional area of the roof space.
Find and determine the maximum height of the roof.
Use the trapezoidal rule with 4 intervals to estimate the cross-sectional area.
Compare the estimate from part 2 with the exact area found by integration.
A sculpture's height, , in meters, is modeled by a cubic function over a 9-meter base, where is the distance from one end in meters. The heights at specific distances are given in the following table:
| (m) | 0 | 3 | 6 | 9 |
|---|---|---|---|---|
| (m) | 1 | 2.5 | 3 | 2 |
Use the trapezoidal rule with 3 intervals to estimate the area under the curve.
Assume . Use the given points to find two linear equations in .
Sketch the graph of and shade the region used in part (a).
A transportation company is studying the velocity of a delivery vehicle over time, modeled by the function in meters per second, from to seconds.
Divide the interval into 4 equal sub-intervals. Write the values of at each endpoint.
Calculate the values of the function at each endpoint.
Use the trapezoidal rule with these values to approximate the total distance travelled by the particle.
Verify the result by calculating the exact integral of over the interval .
Compare the approximation with the exact answer and state which is larger. Explain why the difference might occur.
A renewable energy company is analyzing the growth of a new type of solar panel's instantaneous power output over time. The power output is modeled by the function (in kilowatts) over the interval years.
Divide the interval into 4 equal sub-intervals and write down the values of at each endpoint.
Use the trapezoidal rule with 4 sub-intervals to approximate the total energy produced (area under the curve ) from to .
Use your calculator to find the exact value of the total energy produced and compare it with the approximation from Part 2.
A scientist models the concentration of a chemical in a solution, , in , over 5 hours, using . The total amount of chemical is proportional to the area under the curve. Measurements are taken hourly:
| (h) | 0 | 1 | 2 | 3 | 4 | 5 |
|---|---|---|---|---|---|---|
| (mg/L) | 2 | 2.70 | 3.64 | 4.95 | 6.70 | 9.07 |
Use the trapezoidal rule with 5 intervals to estimate the total amount of chemical.
Show that .
Using part 2, explain how a linear regression on transformed data could confirm the model's parameters.
Find the exact total amount of chemical using integration.
Calculate the absolute error of the trapezoidal estimate.
Suggest one way to improve the trapezoidal rule estimate's accuracy.
A cylindrical container's radius, , in centimeters, varies with height , in centimeters, from the base. The volume of liquid it can hold is given by . The radii are measured at cm intervals as follows:
| (cm) | 0 | 1 | 2 | 3 | 4 | 5 |
|---|---|---|---|---|---|---|
| (cm) | 3 | 4 | 5 | 4 | 3 | 2 |
Use the trapezoidal rule with 5 intervals to estimate the volume of the container.
Sketch the graph of against and shade the region used to estimate the volume in part 1.
A city is planning to build a new park. The shape of the park is defined by the region bounded by the curve , the -axis, and the vertical line , where and are measured in kilometers.
Divide the interval into 4 equal sub-intervals and state the -values.
Calculate the value of at each endpoint.
Use the trapezoidal rule with these 4 sub-intervals to approximate the area of the park.
Calculate the exact area of the park by integrating from 0 to 2.
Compare the approximation with the exact value and explain the difference.
A designer models the height of an arch, , in meters, over a 10-meter span, where is the horizontal distance from the left support. The arch's height is given by , for . The area under the arch represents the space available for passage.
Use the trapezoidal rule with 5 intervals to estimate the area under the arch.
Sketch the graph of and shade the region corresponding to the estimate in Part 1.
Find the exact area under the arch using integration.