Question HLPaper 2AnswerUse mathematical induction to prove that dndxn(yepz)=pn−1(pz+n)epz{\frac{d^n}{dx^n}\left(y^{e^{pz}}\right) = p^{n-1}(pz+n)e^{pz}}dxndn(yepz)=pn−1(pz+n)epz for n∈Z+n \in \mathbb{Z}^+n∈Z+, p∈Qp \in \mathbb{Q}p∈Q.
