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    HLPaper 1

    A collection of data consists of five valuesx1, x2, x3, x4, x5x_{1},\,x_{2},\,x_{3},\,x_{4},\,x_{5}x1​,x2​,x3​,x4​,x5​which have been arranged in ascending order.

    1.

    Recalling definitions, such as the Lower Quartile is the n+14{\frac{{n + 1}}{4}}4n+1​th piece of data with the data arranged in order, find an expression for the Interquartile Range.

    [2]
    Verified
    Solution

    LQ=x1+x22, UQ=x4+x52, IQR=x4+x5−x1−x22{LQ = \frac{{x_1 + x_2}}{2},\ UQ = \frac{{x_4 + x_5}}{2},\ IQR = \frac{{x_4 + x_5 - x_1 - x_2}}{2}}LQ=2x1​+x2​​, UQ=2x4​+x5​​, IQR=2x4​+x5​−x1​−x2​​ [2 marks]

    2.

    Hence, demonstrate that a data set with only 5 values in it cannot have any outliers.

    [5]
    Verified
    Solution

    UQ+1.5IQR=1.25x4+1.25x5−0.75x1−0.75x2⩾x5UQ + 1.5IQR = 1.25{x_4} + 1.25{x_5} - 0.75{x_1} - 0.75{x_2} \geqslant {x_5}UQ+1.5IQR=1.25x4​+1.25x5​−0.75x1​−0.75x2​⩾x5​

    M1A1

    Since1.25x4+0.25x5⩾0.75x1+0.75x21.25{x_4} + 0.25{x_5} \geqslant 0.75{x_1} + 0.75{x_2}1.25x4​+0.25x5​⩾0.75x1​+0.75x2​due to the ascending order.R1

    SimilarlyLQ−1.5IQR=1.25x1+1.25x2−0.75x4−0.75x5⩽x1LQ - 1.5IQR = 1.25{x_1} + 1.25{x_2} - 0.75{x_4} - 0.75{x_5} \leqslant {x_1}LQ−1.5IQR=1.25x1​+1.25x2​−0.75x4​−0.75x5​⩽x1​M1A1

    Since0.25x1+1.25x2⩽0.75x3+0.75x40.25{x_1} + 1.25{x_2} \leqslant 0.75{x_3} + 0.75{x_4}0.25x1​+1.25x2​⩽0.75x3​+0.75x4​due to the ascending order.

    So there are no outliers for a data set of 5 values. AG

    [5 marks]

    3.

    Provide an example of a collection of data with 7 values in it that does have an outlier, justify this fact by stating the Interquartile Range.

    [2]
    Verified
    Solution

    For example 1, 2, 3, 4, 5, 6, 100 whereIQR=4IQR = 4IQR=4 A1A1 [2 marks]

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