What is the percentage yield when 2.0 g of ethene, $C_2H_4$, is formed from 5.0 g of ethanol, $C_2H_5OH$?

$\frac{2.0}{28} \times \frac{5.0}{46} \times 100$

$\frac{\frac{2.0}{28}}{\frac{5.0}{46}} \times 100$

$\frac{28}{2.0} \times \frac{5.0}{46} \times 100$

$\frac{\frac{28}{2.0}}{\frac{5.0}{46}} \times 100$