A proton has a total energy 1050 MeV after being accelerated from rest through a potential difference V.

total energy is the sum of the rest energy and the kinetic energy 1 mark

« $p^2c^2=1050^2-938^2$ therefore» $p=472$ «MeV$c^{-1}$» 1 mark

$\gamma=\frac{1050}{938}=1.12$ 1 mark

$v=0.45c$

OR

$V=1.35 \times 10^8$ «ms$^{-1}$» 1 mark