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    HLPaper 2
    1.

    Express the binomial coefficient (3k+13k−2){\binom{3k+1}{3k-2}}(3k−23k+1​) as a polynomial in k{k}k.

    [3]
    Verified
    Solution
    • This question is from an exam for a previous syllabus, and may contain minor differences in marking or structure.

    (3k+1 3k−2)=(3k+1)!(3k−2)!3!\left( \begin{gathered} 3k + 1 \\\ 3k - 2 \end{gathered} \right) = \frac{{\left( {3k + 1} \right)!}}{{\left( {3k - 2} \right)!3!}}(3k+1 3k−2​)=(3k−2)!3!(3k+1)!​ (M1)

    =(3k+1)3k(3k−1)3! = \frac{{\left( {3k + 1} \right)3k\left( {3k - 1} \right)}}{{3!}}=3!(3k+1)3k(3k−1)​ A1

    =92k3−12k = \frac{9}{2}{k^3} - \frac{1}{2}k=29​k3−21​k or equivalent A1

    [3 marks]

    2.

    Hence find the least value of kkk for which (3k+1 3k−2 )>106\left( \begin{gathered} 3k + 1 \\\ 3k - 2 \\\ \end{gathered} \right) > {10^6}​3k+1 3k−2 ​​>106.

    [3]
    Verified
    Solution

    attempt to solve=92k3−12k>106 = \frac{9}{2}{k^3} - \frac{1}{2}k > {10^6}=29​k3−21​k>106 (M1)

    k>60.57…k > 60.57 \ldots k>60.57… (A1)

    Note: Allow equality.

    ⇒k=61 \Rightarrow k = 61⇒k=61 A1

    [3 marks]

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