A tube is closed at one end and open at the other.
(a) the fundamental mode of the standing wave in the tube.
(b) the position of the node and antinode.
Practice IB Physics Topic C.4 Standing Waves and Resonance with authentic exam-style questions for both SL and HL students. This question bank focuses on the exact syllabus content for C.4 Standing Waves and Resonance and mirrors Paper 1A, 1B, 2 style where relevant.
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A tube is closed at one end and open at the other.
(a) the fundamental mode of the standing wave in the tube.
(b) the position of the node and antinode.
A string of length is fixed at both ends and supports standing waves. The wave speed is .
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(c) the length of the tube in terms of the wavelength.
Which of the following best explains why the sound intensity sharply increases when a pipe reaches its resonant length for a particular frequency?
A standing wave is formed on a string. What is always true at a node?
In a tube closed at one end, which statement is correct regarding the air displacement at each end?
The pipe absorbs all the incoming sound energy
The wavelength becomes smaller than the pipe length
The wave is reflected and undergoes constructive interference
The wave frequency matches the pipe's natural frequency, causing destructive interference
The amplitude is maximum
The string moves at maximum speed
The displacement is always zero
The displacement is maximum
Both ends are nodes of displacement
Both ends are antinodes of displacement
Closed end is a node, open end is an antinode
Closed end is an antinode, open end is a node