MYP Extended Mathematics Topic 5.3 Rational Algebraic…

Make $x$ the subject of the following formula:

\frac{1}{x} + \frac{1}{y} = \frac{1}{z}

Solve for $x$ in terms of $y$ for the equation:

y = \frac{x}{x + 2}

Rearrange the formula for the volume of a cone, $V = \frac{1}{3}\pi r^2 h$ , to make the height $h$ the subject.

True or False: For the rational expression

\frac{2x + 1}{x^2 + 9}

there are no real-valued restrictions on $x$ .

Simplify the following expression:

\frac{x}{x-1} + \frac{1}{1-x}

$x = \frac{yz}{z-y}$

$x = \frac{yz}{y-z}$

$x = \frac{y-z}{yz}$

$x = \frac{2y}{1 - y}$

$x = \frac{2y}{y - 1}$

$x = \frac{y - 2}{y}$

$x = \frac{1 - y}{2y}$

$h = \frac{3V}{\pi r^2}$

$h = \frac{\pi r^2}{3V}$

$h = \frac{V}{3\pi r^2}$

MYP Extended Mathematics 5.3 Rational Algebraic Expressions Questionbank