Question Type 5: Finding both possible triangles for those suffering with Ambigious case of sine rule Exercises

In triangle ABC, $a=15$, $b=17$ and $A=45^\circ$. Determine both possible triangles (angles $B$, $C$, side $c$).

In triangle ABC, $a=14$, $b=20$ and $A=25^\circ$. Find both possible values of $B$, $C$ and $c$.

In triangle $ABC$, $a=5$, $b=6$ and $\sin A = 0.8$. Determine both possible sets of values for angle $B$, angle $C$, and the side $c$.

In triangle ABC, $a=8$, $b=9$ and $A=30^\circ$. Find both possible sets of angles $B$, $C$ and side $c$.

In triangle $ABC$, $a=7$, $b=9$ and $A=40^\circ$. Find both possible values of $B$, $C$ and $c$.

In triangle $ABC$, $a = 11$, $b = 13$ and $\hat{A} = 35^\circ$. Determine both possible triangles, finding the values for angles $B$ and $C$, and side length $c$.

In triangle $ABC$, $a=6$, $b=8$ and $A=25^\circ$. Determine both possible triangles by finding the missing angles $B$ and $C$, and the side length $c$.

In triangle $ABC$, $a = 9$, $b = 14$ and $A = 20^\circ$. Find both possible values of $B$, $C$, and $c$.

In triangle $ABC$, $a=12$, $b=14$ and $A=50^\circ$. Determine both possible triangles, stating the values for angle $B$, angle $C$, and side $c$.

In triangle $ABC$, $a = 10$, $b = 11$, and $\hat{A} = 50^\circ$. Find both sets of possible values for $\hat{B}$, $\hat{C}$, and side $c$.

In triangle $ABC$, $a = 9$, $b = 10$, and $A = 60^\circ$. Find both sets of possible values for angle $B$, angle $C$, and side $c$.

In triangle $ABC$, $a = 6$, $b = 6.2$ and $A = 70^\circ$. Determine both possible triangles by finding the angles $B$, $C$ and the side $c$ for each case.