IB Mathematics Applications & Interpretation Question Type 3: Finding the Products of Matrices Exercises

Calculate the product of the matrices $$A=\left(\begin{array}{ccc}2& 1& -3\\ 0& 4& 2\\ -1& 5& 1\end{array}\right),B=\left(\begin{array}{c}3\\ -2\\ 4\end{array}\right).$$

Calculate the product of the matrices $$A=\left(\begin{array}{ccc}-2& 4& 1\\ 3& -1& 0\\ 2& 2& -3\end{array}\right),B=\left(\begin{array}{ccc}1& 3& -2\\ 0& -1& 4\\ 5& 2& 1\end{array}\right).$$

Calculate the product $AB$ of the matrices $$A=\left(\begin{array}{cc}2& -1\\ 3& 4\end{array}\right),B=\left(\begin{array}{cc}5& 2\\ -3& 1\end{array}\right).$$

Calculate the product of the matrices $$A=\left(\begin{array}{c}1\\ -2\\ 3\end{array}\right),B=\left(\begin{array}{cccc}2& 0& 5& -1\end{array}\right).$$

Calculate the product of the matrices $$A=\left(\begin{array}{cc}1& 2\\ 3& 4\end{array}\right),B=\left(\begin{array}{ccc}0& 5& 1\\ -2& 3& 4\end{array}\right).$$

Calculate the product of the matrices $$A=\left(\begin{array}{ccc}1& 2& 3\\ -1& 0& 4\\ 2& -2& 1\\ 5& 1& -3\end{array}\right),B=\left(\begin{array}{cc}0& 3\\ 1& -1\\ 2& 2\end{array}\right).$$

Calculate the product of the matrices $$A=\left(\begin{array}{ccc}2& -3& 1\end{array}\right),B=\left(\begin{array}{cc}4& 0\\ -1& 5\\ 3& 2\end{array}\right).$$

Calculate the product $AB$ of the matrices: $$A=\left(\begin{array}{cccc}2& -1& 3& 0\\ 1& 4& -2& 5\end{array}\right),B=\left(\begin{array}{cc}1& 2\\ -1& 0\\ 3& -2\\ 2& 1\end{array}\right)$$

Calculate the product of the matrices $$A=\left(\begin{array}{ccc}3& -1& 2\\ 0& 4& 5\end{array}\right),B=\left(\begin{array}{cc}2& 3\\ -1& 1\\ 4& 0\end{array}\right).$$

Calculate the product of the matrices $$A=\left(\begin{array}{cc}1& 2\\ 3& 0\\ -1& 4\\ 2& -3\end{array}\right),B=\left(\begin{array}{cccc}5& -1& 2& 0\\ 1& 3& -2& 4\end{array}\right).$$

Calculate the product of the matrices $$A=\left(\begin{array}{ccc}4& 4& 1\\ 2& 9& 3\end{array}\right),B=\left(\begin{array}{c}4\\ 7\\ 2\end{array}\right).$$

Calculate the product of the matrices $$A=\left(\begin{array}{ccc}1& 0& 2\\ -1& 3& 1\\ 4& 2& -2\end{array}\right),B=\left(\begin{array}{ccc}2& 1& 0\\ -1& 3& 5\\ 4& -2& 1\end{array}\right).$$