- IB
- Question Type 2: Finding the equation of a perpendicular bisector given a line segment with a mid point
Find the equation of the perpendicular bisector of the segment on the line with midpoint at .
[5]Find the equation of the perpendicular bisector of the segment on the line with midpoint at .
[5]Find the equation of the perpendicular bisector of the segment on the line with midpoint at .
[4]This question requires students to determine the equation of a line that is perpendicular to a given line and passes through a specific point (the midpoint of a segment on that line). It tests knowledge of coordinates, perpendicular gradients, and the general form of a linear equation.
Find the equation of the perpendicular bisector of a line segment on the line which has its midpoint at . Give your answer in the form , where .
[6]Find the equation of the perpendicular bisector of the segment on the line with midpoint at .
[5]Find the equation of the perpendicular bisector of the segment on the line with midpoint at .
[5]Find the equation of the perpendicular bisector of the segment on the line with midpoint at .
[5]The perpendicular bisector of a line segment is the line that is perpendicular to the segment and passes through its midpoint. To find the equation of a line, the slope and a point on the line are required. For perpendicular lines with slopes and , the relationship is .
Find the equation of the perpendicular bisector of the line segment on the line with midpoint at . Give your answer in the form , where .
[4]The question tests understanding of coordinate geometry, specifically finding midpoints, perpendicular gradients, and the equation of a line.
Find the equation of the perpendicular bisector of the segment on the line with midpoint at .
[5]Find the equation of the perpendicular bisector of the segment on the line with midpoint at .
[4]Find the equation of the perpendicular bisector of the segment on the line with midpoint at .
[5]Find the equation of the perpendicular bisector of the segment on the line with midpoint at .
[5]