Number and Algebra
Functions
Geometry & Trigonometry
Statistics & Probability
Calculus
Find the area under the curve f(x)=ln(x+1)f(x)=\ln(x+1)f(x)=ln(x+1) between x=0x=0x=0 and x=1x=1x=1.
Determine the area under f(x)=11+x3f(x)=\frac{1}{1+x^3}f(x)=1+x31 from x=0x=0x=0 to x=2x=2x=2 using technology.
Use technology to approximate the area under f(x)=e−x2f(x)=e^{-x^2}f(x)=e−x2 from x=0x=0x=0 to x=1x=1x=1.
Calculate the value of the definite integral ∫01(exln(2x)−x4) dx\int_{0}^{1}(e^x\ln(2x)-x^4)\,dx∫01(exln(2x)−x4)dx.
Use technology to approximate the area under f(x)=1+x4f(x)=\sqrt{1+x^4}f(x)=1+x4 from x=0x=0x=0 to x=1x=1x=1.
Use technology to find the area under f(x)=xx2+1f(x)=\frac{x}{x^2+1}f(x)=x2+1x from x=0x=0x=0 to x=3x=3x=3.
Calculate the exact value of the area under the curve f(x)=xln(x)f(x)=x\ln(x)f(x)=xln(x) from x=1x=1x=1 to x=2x=2x=2. Verify your answer numerically.
Approximate the area under f(x)=x3+1f(x)=\sqrt{x^3+1}f(x)=x3+1 between x=0x=0x=0 and x=2x=2x=2 using a calculator.
Find the area under f(x)=arctan(x)f(x)=\arctan(x)f(x)=arctan(x) from x=0x=0x=0 to x=1x=1x=1.
Previous
Question Type 3: Calculating the area between a polynomial in the positive section and the x axis
Next
No next topic