Number and Algebra
Functions
Geometry & Trigonometry
Statistics & Probability
Calculus
Simplify secā”xācosā”xtanā”x\displaystyle\frac{\sec x-\cos x}{\tan x}tanxsecxācosxā into a single expression in terms of sinā”x\sin xsinx and cosā”x\cos xcosx.
Given tanā”x+secā”x=k\tan x+\sec x=ktanx+secx=k, express sinā”x\sin xsinx in terms of kkk.
Given 2sinā”x+3cosā”x=02\sin x + \sqrt{3}\cos x = 02sinx+3ācosx=0, solve for tanā”x\tan xtanx.
Express tanā”x\tan xtanx in terms of sinā”x\sin xsinx only, using cosā”x=1āsinā”2x\cos x=\sqrt{1-\sin^2 x}cosx=1āsin2xā.
Simplify 1+sinā”xcosā”x\displaystyle\frac{1+\sin x}{\cos x}cosx1+sinxā and show that it equals tanā”x+secā”x\tan x+\sec xtanx+secx.
Simplify (secā”x+tanā”x)(secā”xātanā”x)(\sec x+\tan x)(\sec x-\tan x)(secx+tanx)(secxātanx) into a constant, expressing each function in terms of sinā”x\sin xsinx and cosā”x\cos xcosx.
Express tanā”x\tan xtanx in terms of sinā”x\sin xsinx and cosā”x\cos xcosx.
Express tanā”x\tan xtanx in terms of secā”x\sec xsecx only by rearranging 1+tanā”2x=secā”2x1+\tan^2 x=\sec^2 x1+tan2x=sec2x.
Rearrange 1+tanā”2x=secā”2x1+\tan^2 x=\sec^2 x1+tan2x=sec2x to express tanā”2x\tan^2 xtan2x in terms of cosā”x\cos xcosx only.
Simplify sinā”2xācosā”2xsinā”xcosā”x\displaystyle\frac{\sin^2 x-\cos^2 x}{\sin x \cos x}sinxcosxsin2xācos2xā to express it in terms of tanā”x\tan xtanx and cotā”x\cot xcotx.
Express cosecĀ x\text{cosec } xcosecĀ x in terms of sinā”x\sin xsinx only.
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