Splitting Patterns in Proton Nuclear Magnetic Resonance ('H NMR) Spectroscopy
What Causes Splitting in 'H NMR?
- When you observe an 'H NMR spectrum, you’ll notice that some signals are not just single peaks: they are split into clusters of peaks (e.g., doublets, triplets, quartets).
- This splitting provides crucial information about the number of neighboring hydrogen atoms (protons) near the hydrogen responsible for that signal.
- The splitting occurs because of a phenomenon called spin-spin coupling.
- Each hydrogen nucleus has a magnetic moment (a tiny magnetic field) due to its nuclear spin.
- When hydrogen atoms are close to each other (on neighboring carbon atoms), their magnetic fields interact.
- This interaction causes the signal of one hydrogen to split into multiple peaks.
The $n+1$ Rule for Splitting Patterns
- The splitting pattern of a signal is determined by the n+1 rule. This rule states:
- The number of peaks in a signal = n + 1, where n is the number of equivalent neighboring hydrogen atoms.
Key Points:
- Neighboring hydrogens are those attached to adjacent carbon atoms.
- Hydrogens that are chemically equivalent (in the same chemical environment) do not split each other’s signals.
- The number of peaks in the splitting pattern corresponds to n + 1.
- When counting neighboring hydrogens, focus on hydrogens attached to carbons directly adjacent to the carbon of the hydrogen being analyzed.
- Ignore hydrogens that are further away or part of equivalent groups.
Common Splitting Patterns
Let’s explore the most common splitting patterns and what they tell you:
Singlet
- Number of neighboring hydrogens (n): 0
- Number of peaks: 1
- Appearance: A single peak.
- Interpretation: The hydrogen responsible for this signal has no neighboring hydrogens.
The methyl group in $CH_3-O-CH_3$ (dimethyl ether) produces a singlet because the hydrogens on each $CH_3$ group have no adjacent hydrogens.
Doublet
- Number of neighboring hydrogens (n): 1
- Number of peaks: 2
- Appearance: Two peaks of equal intensity.
- Interpretation: The hydrogen responsible for this signal is adjacent to one hydrogen.
In $CH_3CHCl_2$ (1,1-dichloroethane), the $CH_3$ group produces a doublet because it is adjacent to a single $CH$ proton.
Triplet
- Number of neighboring hydrogens (n): 2
- Number of peaks: 3
- Appearance: Three peaks with an intensity ratio of 1:2:1.
- Interpretation: The hydrogen responsible for this signal is adjacent to two hydrogens.
In $CH_3CH_2OH$ (ethanol), the $CH_3$ group produces a triplet because it is adjacent to the $CH_2$ group with two hydrogens.
Quartet
- Number of neighboring hydrogens (n): 3
- Number of peaks: 4
- Appearance: Four peaks with an intensity ratio of 1:3:3:1.
- Interpretation: The hydrogen responsible for this signal is adjacent to three hydrogens.
In $CH_3CH_2OH$ (ethanol), the $CH_2$ group produces a quartet because it is adjacent to the $CH_3$ group with three hydrogens.
Multiplets and Complex Patterns
- When a hydrogen is influenced by multiple groups of non-equivalent neighboring hydrogens, more complex splitting patterns can arise.
- These are often referred to as multiplets and require more advanced analysis.
Splitting patterns beyond a quartet (e.g., quintets, sextets) are less common but follow the same principles of the $n+1$ rule.
Interpreting a Splitting Pattern
Let’s analyze the splitting patterns in the 'H NMR spectrum of $CH_3CHBr_2$ (1,1-dibromoethane).
- Step 1: Identify the hydrogen environments.
- The molecule has two distinct hydrogen environments: $CH_3$ and CH.
- Step 2: Analyze the $CH_3$ group.
- The $CH_3$ group is adjacent to the CH group, which has one hydrogen.
- According to the n+1 rule, the $CH_3$ group’s signal will be split into n+1 = 1+1 = 2 peaks (a doublet).
- Step 3: Analyze the CH group.
- The CH group is adjacent to the $CH_3$ group, which has three hydrogens.
- According to the n+1 rule, the CH group’s signal will be split into n+1 = 3+1 = 4 peaks (a quartet).
- Result:
- The 'H NMR spectrum will show a doublet for the $CH_3$ group and a quartet for the CH group.
- Based on the n+1 rule, can you predict the splitting pattern for the hydrogens in $CH_3CH_2CH_2OH$?
- Which groups would produce triplets, doublets, or singlets?
- Many students forget that equivalent hydrogens (in the same chemical environment) do not split each other’s signals.
- Always count only non-equivalent neighboring hydrogens when using the $n+1$ rule.


