Interpretation and Applications of Mass Spectra
- You’re handed an unknown element sample and asked to identify it.
- What steps would you take? How would you handle the challenge if the element has multiple isotopes?
This is where mass spectrometry becomes an invaluable tool.
Using Mass Spectra to Identify Isotopes and Their Relative Abundances
What Does a Mass Spectrum Display?
Mass spectrum
A mass spectrum is a graph that plots the relative abundance of ions (y-axis) against their mass-to-charge ratio (m/z) (x-axis).
- In most cases, the charge (z) is +1, meaning the m/z value directly corresponds to the ion's mass.
- Each peak on the spectrum represents a specific isotope or molecular fragment.
Identifying Isotopes
- For elements, each peak corresponds to an isotope.
- The m/z value of the peak indicates the isotope’s mass number, while the peak height(or intensity) reflects its relative abundance.
Mass Spectrum of Chlorine

- The mass spectrum of chlorine reveals two main peaks at m/z = 35 and m/z = 37.
- These peaks represent chlorine’s two naturally occurring isotopes: chlorine-35 and chlorine-37.
- The relative heights of the peaks indicate their abundances:
- Chlorine-35 (m/z = 35): Higher peak, showing greater abundance.
- Chlorine-37 (m/z = 37): Lower peak, showing lesser abundance.
- If the relative abundances are 75.8% for chlorine-35 and 24.2% for chlorine-37, the relative atomic mass of chlorine can be calculated as follows: $$\text{Ar} = \frac{(35 \times 75.8) + (37 \times 24.2)}{100} = 35.45$$
- This value matches the relative atomic mass of chlorine listed in the periodic table.
Determining Relative Abundance
To calculate the relative abundance of isotopes:
- Measure the height (or area) of each peak.
- Divide each peak’s height by the total height of all peaks.
- Multiply by 100 to express the result as a percentage.
Interpreting a Mass Spectrum Step-by-Step
To interpret a mass spectrum effectively:
- Identify the molecular ion peak $M^+$: This peak gives the molecular mass of the compound.
- Look for isotopic peaks: These highlight the presence of elements with multiple isotopes.
- Analyze fragmentation patterns: Use the m/z values of the fragments to deduce the molecule’s structure.
- Calculate relative atomic mass: For elements, use the isotopic abundances to calculate the weighted average.
Boron
- The mass spectrum of boron shows two peaks:
- m/z = 10 (relative abundance = 19.9%)
- m/z = 11 (relative abundance = 80.1%)
- Calculate the relative atomic mass of boron: $$\text{Ar} = \frac{(10 \times 19.9) + (11 \times 80.1)}{100} = 10.8$$
- This value aligns with the periodic table’s relative atomic mass for boron.
- Many students mistakenly identify fragment peaks as the molecular ion peak.
- Remember, the molecular ion peak corresponds to the entire molecule and typically has the highest m/z value (excluding isotopic peaks).
Calculating the Relative Atomic Mass of a Diatomic Element from a Mass Spectrum
To calculate the relative atomic mass of a diatomic element like chlorine ($Cl_2$) or bromine ($Br_2$) using a mass spectrum:
- Identify the Isotopes Present:



