On a velocity-time graph, a line starts in the negative region (below the horizontal axis) and slopes upwards towards the time axis. This represents an object that is:

Moving in the positive direction and speeding up

Moving in the positive direction and slowing down

Moving in the negative direction and slowing down

Moving in the negative direction and speeding up

Question

A velocity–time graph shows a horizontal line at $v = 0$ for a period of $10\ \text{s}$ . What can be concluded about the object's displacement during this time?

In a velocity–time graph, the total displacement of an object over a time interval is equal to the __________ under the graph.

A toy car moves $6.0\ \text{m}$ forward (positive direction) in $2.0\ \text{s}$ and then $2.0\ \text{m}$ backward in $2.0\ \text{s}$ . What is the average velocity for the entire trip?

An object travels $100\ \text{m}$ along a winding path and eventually returns to its exact starting position. The entire journey takes $20\ \text{s}$ . What are the average speed and the magnitude of the average velocity for this journey?

MYP MYP Physics Topic Speed, Motion Graphs Questionbank

Practice MYP MYP Physics Topic Speed, Motion Graphs with authentic exam-style questions for both SL and HL students. This question bank focuses on the exact syllabus content for Speed, Motion Graphs and mirrors Paper 1, 2 style where relevant.

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2.0

4.0\ \text{s}

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The displacement is constant

The displacement is increasing at a constant rate

The displacement is equal to the area of a rectangle

The displacement is decreasing at a constant rate

Area

Inverse of the gradient

Gradient

Final velocity value

Average speed = $5\ \text{m s}^{-1}$ ; Average velocity = $5\ \text{m s}^{-1}$

Average speed = $2000\ \text{m s}^{-1}$ ; Average velocity = $0\ \text{m s}^{-1}$

Average speed = $5\ \text{m s}^{-1}$ ; Average velocity = $0\ \text{m s}^{-1}$

Average speed = $0\ \text{m s}^{-1}$ ; Average velocity = $5\ \text{m s}^{-1}$

$0.5\ \text{m s}^{-1}$

$1.0\ \text{m s}^{-1}$

$2.0\ \text{m s}^{-1}$

$1.5\ \text{m s}^{-1}$