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Mole
The amount of substance that contains $N_A=6.022×10^{23}$ particles (atoms, molecules, ions, etc.).
That big number in the definition of the mole is called Avogadro’s constant.
Think of a mole as a chemist’s dozen:
The most frequently used values:
These numbers have no units when used as Aᵣ, but the molar mass has units of g mol⁻¹ and is numerically equal to Mᵣ.
Water – H₂O
$$M_r\left(\mathrm{H}_2 \mathrm{O}\right)=2 \times A_r(\mathrm{H})+A_r(\mathrm{O})=2 \times 1+16=18$$
So molar mass = 18 g mol⁻¹
Sodium chloride – NaCl
$$M_r(\mathrm{NaCl})=A_r(\mathrm{Na})+A_r(\mathrm{Cl})=23+35.5=58.5$$
Molar mass = 58.5 g mol⁻¹
Calcium hydroxide – Ca(OH)₂
Be careful with brackets – (OH)₂ means two OH groups:
$$M_r\left(\mathrm{Ca}(\mathrm{OH})_2\right)=A_r(\mathrm{Ca})+2 \times\left[A_r(\mathrm{O})+A_r(\mathrm{H})\right]=40+2 \times(16+1)=$$ $$=40+2 \times 17=40+34=74$$
Molar mass = 74 g mol⁻¹
Diatomic gases
Some elements exist as diatomic molecules in nature: H₂, N₂, O₂, F₂, Cl₂, Br₂, I₂.
Example for O₂: $$M_r\left(\mathrm{O}_2\right)=2 \times 16=32$$
When you see O₂, H₂, Cl₂ in an equation, always use the molecular Mr, not the atomic Ar.
$$n=\frac{m}{M}$$
Where:
How many moles are in 36.0 g of water?
Solution
$$M\left(\mathrm{H}_2 \mathrm{O}\right)=18.0 \mathrm{~g} \mathrm{~mol}^{-1} \Rightarrow n=\frac{36.0}{18.0}=2.0 \mathrm{~mol}$$
What mass is 2.0 mol of H₂O?
Solution
$$m=n M=2.0 \times 18.0=36.0 \mathrm{~g}$$
Once you know the moles, you can find the number of particles using Avogadro’s constant: $$N=n \times N_A$$
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