Calculate P(X>5) for X∼N(2,4).
Let X∼N(2,σ2) and P(X>a)=0.3. Find 1−P(X<4−a).
For X∼N(8,σ2), if 95% of the data lies between 6.5 and 9.5, find the value of σ2.
The use of a graphic display calculator (GDC) is expected for finding normal distribution values.
A test score is modeled by a normal distribution X∼N(100,σ2). Given that 80% of students score between 90 and 110, find the value of σ2.
The random variable X follows a normal distribution with mean μ=0 and variance σ2=9. Find the probability that X lies within the interval [−1,2].
Calculate P(−1≤X≤2) for X∼N(0,9).
For X∼N(3,16), show that P(X<−1)=P(X>7) and compute this probability.
Mathematics: analysis and approaches
Let X∼N(2,σ2) and P(X>a)=0.3. Express a in terms of σ.
Calculate P(X<1.96) for X∼N(0,1).
For X∼N(0,σ2), if 95% of the data lies between −3 and 3, find σ.
For X∼N(10,σ2), the central 90% of the data lies between 8 and 12. Find the value of σ.
This question assesses the ability to use the standard normal distribution and symmetry to find an unknown parameter of a normal distribution.
Let X∼N(5,σ2). Given that 99% of the data lies between 3 and 7, find the value of σ.
For X∼N(20,σ2), the interval [10,30] contains 95% of the values. Find σ2.
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