Number and Algebra
Functions
Geometry and Trigonometry
Statistics and Probability
Calculus
Calculate the slopes at the points (1,1)(1,1)(1,1), (2,0)(2,0)(2,0) and (3,2)(3,2)(3,2) in the slope field for the differential equation
rac{dy}{dx}=rac{x-2y}{x}.
Determine the sign of dydx\displaystyle\frac{dy}{dx}dxdy at the point (2,3)(2,3)(2,3) and state whether solution curves are increasing or decreasing there, given
For x=1x=1x=1, identify the interval(s) of yyy for which the slope field defined by
rac{dy}{dx}=rac{x-2y}{x}
shows positive slopes.
Find all points on the line x=1x=1x=1 where the slope in the slope field is zero for
Using the particular solution found for y(2)=1y(2)=1y(2)=1, calculate the value of yyy when x=3x=3x=3.
Solve the differential equation
to find the general solution y(x)y(x)y(x).
Find the particular solution of
that satisfies the initial condition y(2)=1y(2)=1y(2)=1.
Determine the particular solution passing through (1,0)(1,0)(1,0) for
dydx=x−2yx ,\frac{dy}{dx}=\frac{x-2y}{x}\,,dxdy=xx−2y,
and write its explicit form.
Describe the behavior of the particular solution through (1,0)(1,0)(1,0) as x→0+x\to0^+x→0+.
Determine the xxx–value at which the particular solution through (1,−1)(1,-1)(1,−1) crosses y=0y=0y=0 again, given
dydx=x−2yx .\frac{dy}{dx}=\frac{x-2y}{x}\,.dxdy=xx−2y.
Show that as x→∞x\to\inftyx→∞, the general solution of
dydx=x−2yx\frac{dy}{dx}=\frac{x-2y}{x}dxdy=xx−2y
is asymptotic to a straight line, and determine its equation.
Solve the differential equation by the substitution y=vxy=v xy=vx, find v(x)v(x)v(x), and verify that your result matches the general solution.
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Question Type 2: Sketching a solution curve that passes through a specific point using a slope field diagram