Number and Algebra
Functions
Geometry & Trigonometry
Statistics & Probability
Calculus
Simplify the expression (n+3)!n! .\frac{(n+3)!}{n!}\,. n!(n+3)!.
Simplify the factorial expression (x! y!)!(x! y!−1)! .\frac{(x!\,y!)!}{\bigl(x!\,y! - 1\bigr)!}\,. (x!y!−1)!(x!y!)!.
For x=3x=3x=3, y=2y=2y=2, and k=3k=3k=3, evaluate (x! y!)!(x! y!−k)! .\frac{(x!\,y!)!}{\bigl(x!\,y! - k\bigr)!}\,. (x!y!−k)!(x!y!)!.
Simplify the expression (x! y!+2)!(x! y!)! .\frac{(x!\,y!+2)!}{(x!\,y!)!}\,. (x!y!)!(x!y!+2)!.
Simplify the expression (x! y!)!(x! y!−1)! (x−1)! (y−1)! .\frac{(x!\,y!)!}{\bigl(x!\,y! - 1\bigr)!\,(x-1)!\,(y-1)!}\,. (x!y!−1)!(x−1)!(y−1)!(x!y!)!.
Evaluate (x! y!)!(x! y!−1)! (x−1)! (y−1)!\frac{(x!\,y!)!}{\bigl(x!\,y! - 1\bigr)!\,(x-1)!\,(y-1)!}(x!y!−1)!(x−1)!(y−1)!(x!y!)! for x=2x=2x=2, y=3y=3y=3.
Show that (x! y!+1)!(x! y!−1)!=(x! y!) (x! y!+1) .\frac{(x!\,y!+1)!}{\bigl(x!\,y! - 1\bigr)!}=(x!\,y!)\,(x!\,y!+1)\,. (x!y!−1)!(x!y!+1)!=(x!y!)(x!y!+1).
Evaluate (x! y!)!(x! y!−1)! (x−1)! (y−1)!\frac{(x!\,y!)!}{\bigl(x!\,y! - 1\bigr)!\,(x-1)!\,(y-1)!}(x!y!−1)!(x−1)!(y−1)!(x!y!)! for x=3x=3x=3, y=4y=4y=4.
Express (x! y!)!(x! y!−k)!\frac{(x!\,y!)!}{\bigl(x!\,y! - k\bigr)!}(x!y!−k)!(x!y!)! as a product of kkk consecutive factors. Assume 1≤k≤x! y!1\le k\le x!\,y!1≤k≤x!y!.
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Question Type 4: Finding the values of combinatoric functions