Number and Algebra
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Geometry & Trigonometry
Statistics & Probability
Calculus
Let X∼Bin(10,p)X\sim \text{Bin}(10,p)X∼Bin(10,p). Find the value of ppp such that the mean of XXX is 3.
For X∼Bin(n,p)X\sim \text{Bin}(n,p)X∼Bin(n,p), find ppp in terms of nnn such that the excess kurtosis equals 1−6p(1−p)np(1−p)=1\frac{1-6p(1-p)}{np(1-p)}=1np(1−p)1−6p(1−p)=1.
Find integer n>0n>0n>0 and rational ppp such that for X∼Bin(n,p)X \sim \text{Bin}(n,p)X∼Bin(n,p) the mean is 7.57.57.5 and the variance is 3.753.753.75.
For a binomial random variable X∼Bin(n,p)X\sim \text{Bin}(n,p)X∼Bin(n,p), find expressions for the mean μ\muμ and variance σ2\sigma^2σ2 in terms of nnn and ppp.
Suppose X∼Bin(n,0.2)X \sim \text{Bin}(n,0.2)X∼Bin(n,0.2). Find the smallest integer nnn such that the variance of XXX is at least 4.
Find ppp for X∼Bin(n,p)X\sim \text{Bin}(n,p)X∼Bin(n,p) so that the coefficient of variation CV=1\text{CV}=1CV=1, where CV=σ/μ\text{CV}=\sigma/\muCV=σ/μ.
Given X∼Bin(n,p)X\sim \text{Bin}(n,p)X∼Bin(n,p) with mean 555 and variance 444, find the values of nnn and ppp.
For X∼Bin(n,p)X\sim \text{Bin}(n,p)X∼Bin(n,p), find ppp such that the mean equals the variance.
Find ppp in terms of nnn for X∼Bin(n,p)X\sim \text{Bin}(n,p)X∼Bin(n,p) so that the mean of XXX is twice its variance.
For X∼Bin(20,p)X\sim \text{Bin}(20,p)X∼Bin(20,p), find ppp such that P(X≥1)=0.95P(X\ge1)=0.95P(X≥1)=0.95.
Let X∼Bin(n,p)X \sim \text{Bin}(n,p)X∼Bin(n,p).
Find the value of ppp such that the variance is one quarter of the mean.
If X∼Bin(n,p)X\sim \text{Bin}(n,p)X∼Bin(n,p) satisfies P(X=0)=0.1P(X=0)=0.1P(X=0)=0.1, express nnn in terms of ppp.
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Question Type 1: Finding the probability of outcomes for binomial distribution using the GDC
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