Number and Algebra
Functions
Geometry & Trigonometry
Statistics & Probability
Calculus
Find the equation of the normal to the curve y=ln(x)y=\ln(x)y=ln(x) at x=4x=4x=4.
For the curve y=1xy=\frac{1}{x}y=x1, the tangent at x=−1x=-1x=−1 has slope mmm. Determine the equation of the normal at that point.
Find the equation of the normal to the curve y=xx−1y=\tfrac{x}{x-1}y=x−1x at x=2x=2x=2.
Find the equation of the normal to the curve y=x3−3x+2y = x^3 - 3x + 2y=x3−3x+2 at the point where the tangent has slope 6.
Calculate the equation of the normal to the curve y=e2x+xy = e^{2x} + xy=e2x+x at the point where the tangent has slope 5.
Determine the equation of the normal to the curve y=arctan(x)y=\arctan(x)y=arctan(x) at x=1x=1x=1.
Calculate the equation of the normal to the curve y2=4x+8yy^2=4x+8yy2=4x+8y at the point (0,0)(0,0)(0,0).
Find the equation of the normal to the curve defined by x2+xy+y2=7x^2+xy+y^2=7x2+xy+y2=7 at the point (1,2)(1,2)(1,2).
The curve is y=sinx+xy=\sin x+xy=sinx+x. Find the equation of the normal at the point where its tangent has slope 1.
Find the equation of the normal to the curve x3+y3=6xyx^3+y^3=6xyx3+y3=6xy at the point (3,3)(3,3)(3,3).
Previous
Question Type 1: Finding the tangent and normal to a polynomial at a specific value of x
Next
Question Type 3: Finding the tangent and normal to more complex functions using the GDC at different points