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This curiosity leads us to an important concept in chemistry: molar volume.
Molar volume
The molar volume of a gas is the volume occupied by one mole of an ideal gas under specific conditions of temperature and pressure.
Suppose you have 2 moles of oxygen gas (O₂) at STP. What is the total volume of the gas?
Solution
Boyle's law
Boyle's law states that at constant temperature and for a fixed amount of gas, pressure is inversely proportional to volume.
A gas occupies 4.0 dm³ at a pressure of 100 kPa. If the volume is reduced to 2.0 dm³, what will the new pressure be (assuming constant temperature)?
Solution
Using Boyle’s Law:
$$
p_1V_1 = p_2V_2
$$
$$
100 \, \text{kPa} \times 4.0 \, \text{dm}^3 = p_2 \times 2.0 \, \text{dm}^3
$$
$$
p_2 = \frac{100 \times 4.0}{2.0} = 200 \, \text{kPa}
$$
The pressure doubles to 200 kPa when the volume is halved.
Charles's law
Charles's law states that at constant pressure and for a fixed amount of gas, volume is directly proportional to absolute temperature (in Kelvin).
A gas occupies 3.0 dm³ at 273 K. What will its volume be at 546 K (assuming constant pressure)?
Solution
Using Charles’s Law:
$$
\frac{V_1}{T_1} = \frac{V_2}{T_2}
$$
$$
\frac{3.0 \, \text{dm}^3}{273 \, \text{K}} = \frac{V_2}{546 \, \text{K}}
$$
$$ V_2 = \frac{3.0 \times 546}{273} = 6.0 \, \text{dm}^3 $$
The volume doubles as the temperature doubles (in Kelvin).
Gay-Lussac's law
Gay-Lussac's law states that at constant volume and for a fixed amount of gas, pressure is directly proportional to absolute temperature (in Kelvin).
A gas has a pressure of 150 kPa at 300 K. What will the pressure be at 450 K (assuming constant volume)?
Solution
Using Gay-Lussac’s Law:
$$
\frac{p_1}{T_1} = \frac{p_2}{T_2}
$$
$$
\frac{150 \, \text{kPa}}{300 \, \text{K}} = \frac{p_2}{450 \, \text{K}}
$$
$$
p_2 = \frac{150 \times 450}{300} = 225 \, \text{kPa}
$$
The pressure increases as the temperature increases.