00:00Hi guys, so in this
00:02lesson we're going to find
00:03the intersection point between a
00:05line and a plane out
00:06there I say it but
00:07this is fairly straightforward. So
00:11we've a line and it
00:13passes through a plane. Now
00:15if you think about it
00:16a bit like the way
00:17two lines will always meet.
00:20If you go if you
00:22continue along the line far
00:23enough they'll always meet unless
00:24they're parallel. Well a line
00:27will always meet
00:28a plane as well. If
00:29you just think about that
00:30intuitively, provided they're not parallel.
00:35So if you have like
00:36this lines obviously going to
00:37meet this plane, but if
00:38you had a line not
00:39going straight across like this,
00:42this line is never going
00:43to meet. Is there going
00:44to touch this plane? Now
00:45how can you tell of
00:46a line and a plane
00:47are parallel? Well, a plane
00:50like a plane doesn't have
00:53a direction vector per se.
00:55What it does have
00:56is the normal vector. So
00:58if we have a normal,
01:00what that, if we have
01:02a normal vector coming straight
01:03out like this, this is
01:06perpendicular to the plane. So
01:07if you have a straight
01:08line that's perpendicular to the
01:12normal, then that means the
01:15line is parallel to the
01:16plane and I want to
01:17intersect the plane. So it's
01:19simple as that. And you
01:20can test if it's perpendicular
01:23to the normal,
01:24by doing the dot product
01:27of the direction vector of
01:30the line with the normal,
01:32which in this case will
01:33be 4, negative 3, 2.
01:35Okay, now what I want
01:37to do is find the
01:40point of intersection. So as
01:44the plane pi is defined
01:46by the equation this, find
01:47the point of intersection of
01:48the line L. So this
01:50is L with plane pi.
01:52So this is straightforward because
01:55you have x, you have
01:58y and you have z
01:59in terms of lambda for
02:01the line. So let's actually,
02:04we can write that out.
02:06x equals 6 plus 6
02:08lambda, comma, y equals negative
02:125 minus 8 lambda and
02:16z equals 11 plus
02:2017 lambda. So all we
02:23need to do is sub
02:24these into the equation of
02:27the plane because it's the
02:30point of intersection is the
02:34value of lambda that satisfies
02:36both equations if you like.
02:40So like the equation of
02:41the line and the equation
02:42of the plane. So I'm
02:43going to sub 6 plus
02:446 lambda in for x.
02:46So it's 4 times 6
02:48plus
02:486 lambda minus 3 times
02:51y, which is minus 5
02:53minus 8 lambda, plus 2
02:57times z 11 plus 17
02:59lambda. And this has to
03:02equal 20 multiplied out 24
03:06plus 24 lambda plus 15
03:09plus 24 lambda. Do not
03:12make any mistakes here guys
03:13plus 22 plus 34.
03:16or lambda equals 20. I
03:20doubt my lambda's. 24 plus
03:2324 is 48, 58, 68,
03:2978, 78, 82. So this
03:32is 82 lambda equals, add
03:37this up, 24 plus 15
03:40is 39, 49, 59, 59,
03:44I'm going to get a
03:52nice lambda of negative one
03:55half. Okay, nearly done. How
03:58do I find the point?
03:59Well, I found the lambda,
04:01so I just need to
04:02sub lambda into this. So
04:04therefore, let's, I can write
04:07point of intersection. X is
04:12equal to x.
04:12to 6 plus 6 times
04:16minus 1 1 1 1
04:191 1 1 1 1
04:40times negative a half, which
04:44is going to be, I'm
04:48going to do this the
04:49long way guys, I don't
04:49make it going to take
04:5022 over two minus 17
04:54over two, which is 5
04:58over two. Therefore the point,
05:01therefore point of intersection is
05:08is now guys don't write
05:13this as a vector. It's
05:14a point if they want
05:15a point, give them a
05:16point. So the point is
05:17three negative one, five over
05:21two, or two point five,
05:23if you prefer. I prefer
05:24five or two over two.
05:26Okay, so that's it. Fairly
05:28straightforward as I say. Maybe
05:31the way they can make
05:33the question difficult more difficult
05:35is not give you the
05:36plane in this
05:36form, if that's the case,
05:38put it in this form
05:39and put the line in
05:40this form. Or at least
05:42this form get your x,
05:43get your y, get your
05:44z, sub it in and
05:46find the lambda then find
05:47the point. Okay, hope that
05:49makes sense. See you in
05:51the next lesson.