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Universal set
The set of all elements being considered in a given situation, usually drawn as a rectangle and often labelled $U$.
Subset
A set $A$ is a subset of $B$ (written $A\subseteq B$) if every element of $A$ is also an element of $B$.
Venn diagrams are named after the English mathematician John Venn, who popularized this way of representing logical relationships.
When you learn Venn diagrams, it helps to connect each symbol to a visual idea.
Set intersection
The set of elements that are in both sets. For sets $A$ and $B$, the intersection is $A \cap B$.
Union
The set of elements that are in at least one of the sets. For sets $A$ and $B$, the union is $A \cup B$.
Complement
The set of elements not in a set. The complement of $A$ (relative to $U$) is $A'$.
The overlap of the circles is shaded for $A \cap B$ because an element must satisfy both conditions: it is in $A$ and in $B$.
For $A \cup B$ you shade all of circle $A$ and all of circle $B$. The "or" here is inclusive, so elements in the overlap count too.
In set language, "$A$ or $B$" usually means inclusive or: elements in $A \cap B$ are included in $A \cup B$.
If two sets do not share any elements, their circles do not overlap.
Disjoint sets
Two sets $A$ and $B$ are disjoint if they have no elements in common, so $A \cap B = \varnothing$.
Empty set
Written $\emptyset$, is the set with no elements.
A practical way to avoid mistakes is to shade different sets with different patterns (for example, vertical lines for $A$ and horizontal lines for $B$). Then:
When a set expression is complicated, shade one part at a time using different patterns, then decide what the final shaded region should be.
Complicated expressions are manageable if you follow a consistent routine.
To shade $(A \cap B)'$:
To shade $A \cup (A \cap B)$:
A Venn diagram can help you see a simplification: $A \cup (A \cap B) = A$.
Two extremely useful identities can be validated visually with Venn diagrams.
De Morgan’s laws
For any sets $A$ and $B$ in a universal set $U$,
$$(A \cup B)' = A' \cap B' \quad\text{and}\quad (A \cap B)' = A' \cup B'.$$
Venn diagrams are not only for shading, they also support reasoning.
To show $A \cap B \subseteq A \cup B$, notice:
A diagram makes this visually obvious because the intersection region is completely contained inside the union region.
In applications, sets often represent groups of people or objects with properties.
In a year group of 60 students, 35 study French ($F$), 28 study Spanish ($S$), and 10 study both.
So $n(F \cup S) = 25 + 10 + 18 = 53$ students study at least one language.