Lower and Upper Bounds in Measurement
Lower bound
The lower bound of a rounded or measured quantity is the smallest value the original (exact) quantity could have had, given the stated accuracy.
Upper bound
The upper bound of a rounded or measured quantity is the largest value the original (exact) quantity could have had, given the stated accuracy. For continuous data, the true value is strictly less than this upper bound.
From a Single Number to an Interval
- When a value is reported as a rounded measurement (for example, “16 m to the nearest metre”), the true value is not exactly known.
- Instead, it lies in an interval of possible values.
- The lower bound is the smallest possible value.
- The upper bound is the largest possible value (not included for continuous data).
- Together, these are called the limits of accuracy.
Continuous Measurements Create Ranges, Not Single Values
- Many real measurements are continuous: they can take any value in an interval (for example, height, mass, time, temperature).
- This is different from discrete quantities, which come in fixed steps (like number of students in a class).
- Because continuous measurements are recorded to a stated accuracy (nearest metre, nearest 0.1 kg, 2 significant figures, etc.), you should treat the recorded number as a label for an interval of possible true values, not as an exact value.
Think of the rounded value as the name of a whole neighbourhood of numbers.
- The lower bound is the first house in the neighbourhood.
- The upper bound is just before the last house.
How to Find Bounds from a Rounded Value
- Rounding works by grouping values around a midpoint.
- Suppose a measurement is rounded to the nearest unit of size $a$.
- Examples of step size $a$:
- Nearest 10 → $a=10$
- Nearest 0.1 → $a=0.1$
- Nearest 0.01 → $a=0.01$
- Then the half-step is $\frac{a}{2}$.
- If the recorded (rounded) value is $x$, then
- Lower bound = $x−\frac{a}{2}$
- Upper bound = $x+\frac{a}{2}$
- So the true value TT satisfies $$x-\frac{a}{2} \leq T<x+\frac{a}{2}$$
- We usually include the lower bound but exclude the upper bound.
- This matches the rule that values exactly halfway ($\frac{a}{2}$ above the midpoint) round up.
Nearest Kilogram
A suitcase weighs 16 kg to the nearest kilogram.
- Step size: $a=1 \text{ kg}$
- Half-step: $\frac{a}{2}=0.5 \text{ kg}$
So
- Lower bound: $16−0.5=15.5 \text{ kg}$
- Upper bound: $16+0.5=16.5 \text{ kg}$
The actual mass $w$ satisfies $$15.5 \leq w<16.5$$
- Do not write $15.5 \leq w \leq 16.5$.
- If $w=16.5$, it would round to 17 kg , not 16 kg .
Choosing the Correct Inequality Signs
The inequality signs matter because of how rounding behaves at the midpoint.
A lion’s mass is reported as 300 kg to the nearest 100 kg.
- Step size: $a=100 \text{ kg}$
- Half-step: $\frac{a}{2}=50 \text{ kg}$
- Lower bound: $300−50=250 \text{ kg}$
- Upper bound: $300+50=350 \text{ kg}$
So the true mass mm satisfies $$250 \leq m < 350$$
If the lion actually had mass $m=350 \text{ kg}$, rounding to the nearest 100 kg would give 400 kg (values exactly halfway round up).
When you see “to the nearest …”, immediately:
- Identify the rounding step aa (for example, nearest 5 → a=5a=5).
- Use the structure
$$x-\frac{a}{2} \leq \text{ true value } < x+\frac{a}{2}$$
Even if you later make a small arithmetic slip, this shows a correct method.
Bounds for Decimals and Significant Figures
Nearest Decimal Place
- If a length is 1.6 m to the nearest 0.1 m, then
- Step size: $a=0.1$
- Half-step: $\frac{a}{2}=0.05$
- So the true length $L$ satisfies $1.55 \leq L < 1.65$$
- The lower bound is $1.55 \text{ m}$.
Significant Figures
With significant figures, the step size depends on the place value of the last significant digit.
$22 \text{ kg}$ to 2 significant figures
- The second significant figure is in the ones place.
- So the rounding step is $a=1 \text{ kg}$
- Half-step: $\frac{a}{2}=0.5 \text{ kg}$
Therefore: $$21.5\leq M<22.5$$
$0.7 text{ t}$ to 1 significant figure
- The first significant figure is in the tenths place.
- The rounding step is $a=0.1 \text{ t}$
- Half-step: $\frac{a}{2}=0.05 \text{ t}$
Therefore: $$0.65 \leq T<0.75$$
To find the rounding step for significant figures:
- Identify the place value of the last kept digit.
- Use that place value as the step $a$.
- “Nearest thousand” → $a=1000$, half-step $\frac{a}{2}=500$
- “Nearest 0.01” → $a=0.01$, half-step $\frac{a}{2}=0.005$
Using Bounds in Calculations
- Once you have lower and upper bounds for quantities, you can use them to find maximum and minimum possible results of calculations.
- Let $A$ and $B$ be quantities with bounds. To:
Maximize the result
- $A+B$: use upper bound + upper bound
- $A−B$: use upper bound − lower bound
- $A\times B$: use upper bound × upper bound (if both are positive)
- $\frac{A}{B}$: use upper bound ÷ lower bound (if both are positive)
Minimize the result
- $A+B$: use lower bound + lower bound
- $A−B$: use lower bound − upper bound
- $A\times B$: use lower bound × lower bound (if both are positive)
- $\frac{A}{B}$: use lower bound ÷ upper bound (if both are positive)
These rules match the summary table: to make an answer as big as possible, combine the bounds in a way that pushes the result up; to make it as small as possible, combine them to push the result down.
Why Bounds Matter in Real Decisions
- A lower bound is often the safest guaranteed minimum you can claim.
- If a crate is labelled 40 kg to the nearest 0.5 kg, the minimum possible mass is the lower bound, $39.75 \text{ kg}$.
- When measurements are used for safety limits, capacity planning or costs, working with lower and upper bounds helps avoid over-estimating what is guaranteed.
- Card length: 12.0 cm to the nearest 0.1 cm → upper bound $=12.05 \text{ cm}$
- Envelope length: 12.0 cm to the nearest 0.5 cm → lower bound $=11.75 \text{ cm}$
The largest possible card $(12.05 \text{ cm})$ is bigger than the smallest possible envelope $(11.75 \text{ cm})$, so you cannot guarantee that the card will fit in the envelope.
Packaging and sustainability
- If a manufacturer designs packaging using only rounded measurements, some items may not fit, causing waste and rework.
- Using lower and upper bounds leads to better decisions and more efficient use of materials.
Building and Interpreting Bounds on a Number Line
- A number line helps you visualize the interval idea.
- Mark the stated rounded value in the centre.
- Move left and right by half the rounding step.
- Mark:
- a solid (closed) point at the lower bound (included),
- an open point at the upper bound (excluded).
- A rope is 8 m to the nearest metre. Write the lower bound.
- Mauritius is 2000 km to the nearest 10 km. Write the lower bound.
- A temperature is 23.4°C to 1 decimal place. Write the lower bound.