Introduction
Trigonometric functions and equations form a fundamental part of JEE Main Mathematics. This topic is not only crucial for scoring high in the exam but also forms the basis for many advanced concepts in calculus, algebra, and geometry. In this study note, we will break down the complex ideas into smaller, manageable sections, explain each part clearly, and provide examples where necessary to make the concepts digestible.
Trigonometric Functions
Definition and Basic Functions
Trigonometric functions are functions of an angle that relate the angles of a triangle to the lengths of its sides. The primary trigonometric functions are:
- Sine ($\sin$)
- Cosine ($\cos$)
- Tangent ($\tan$)
- Cosecant ($\csc$)
- Secant ($\sec$)
- Cotangent ($\cot$)
These functions are defined as follows for an angle $\theta$ in a right-angled triangle:
$$ \sin \theta = \frac{\text{Opposite Side}}{\text{Hypotenuse}} $$
$$ \cos \theta = \frac{\text{Adjacent Side}}{\text{Hypotenuse}} $$
$$ \tan \theta = \frac{\text{Opposite Side}}{\text{Adjacent Side}} = \frac{\sin \theta}{\cos \theta} $$
$$ \csc \theta = \frac{1}{\sin \theta} $$
$$ \sec \theta = \frac{1}{\cos \theta} $$
$$ \cot \theta = \frac{1}{\tan \theta} = \frac{\cos \theta}{\sin \theta} $$
NoteThe reciprocal relationships among the trigonometric functions are important for simplifying expressions and solving equations.
Unit Circle Representation
The unit circle is a circle with a radius of 1 centered at the origin of a coordinate plane. It is a powerful tool for understanding trigonometric functions.
- The $x$-coordinate of a point on the unit circle is $\cos \theta$.
- The $y$-coordinate of a point on the unit circle is $\sin \theta$.
For any angle $\theta$, the coordinates $(\cos \theta, \sin \theta)$ represent the point on the unit circle corresponding to that angle.
Diagram: Unit Circle showing angles in radians and corresponding coordinates
TipMemorize the unit circle values for common angles (0, $\pi/6$, $\pi/4$, $\pi/3$, $\pi/2$, etc.) to quickly solve trigonometric problems.
Periodicity and Symmetry
Trigonometric functions are periodic, meaning they repeat their values in regular intervals. The periodicities are:
- $\sin \theta$ and $\cos \theta$ have a period of $2\pi$.
- $\tan \theta$ and $\cot \theta$ have a period of $\pi$.
Symmetry properties:
- $\sin(-\theta) = -\sin \theta$ (Odd function)
- $\cos(-\theta) = \cos \theta$ (Even function)
- $\tan(-\theta) = -\tan \theta$ (Odd function)
Trigonometric Identities
Fundamental Identities
- Pythagorean Identities:
$$ \sin^2 \theta + \cos^2 \theta = 1 $$
$$ 1 + \tan^2 \theta = \sec^2 \theta $$
$$ 1 + \cot^2 \theta = \csc^2 \theta $$
- Angle Sum and Difference Identities:
$$ \sin(a \pm b) = \sin a \cos b \pm \cos a \sin b $$
$$ \cos(a \pm b) = \cos a \cos b \mp \sin a \sin b $$
$$ \tan(a \pm b) = \frac{\tan a \pm \tan b}{1 \mp \tan a \tan b} $$
ExampleFind $\sin(75^\circ)$ using angle sum identities.
$$ \sin(75^\circ) = \sin(45^\circ + 30^\circ) = \sin 45^\circ \cos 30^\circ + \cos 45^\circ \sin 30^\circ $$
Using known values:
$$ \sin 45^\circ = \frac{\sqrt{2}}{2}, \cos 30^\circ = \frac{\sqrt{3}}{2}, \cos 45^\circ = \frac{\sqrt{2}}{2}, \sin 30^\circ = \frac{1}{2} $$
$$ \sin(75^\circ) = \frac{\sqrt{2}}{2} \cdot \frac{\sqrt{3}}{2} + \frac{\sqrt{2}}{2} \cdot \frac{1}{2} = \frac{\sqrt{6}}{4} + \frac{\sqrt{2}}{4} = \frac{\sqrt{6} + \sqrt{2}}{4} $$
Double Angle and Half Angle Identities
- Double Angle Identities:
$$ \sin 2\theta = 2 \sin \theta \cos \theta $$
$$ \cos 2\theta = \cos^2 \theta - \sin^2 \theta = 2\cos^2 \theta - 1 = 1 - 2\sin^2 \theta $$
$$ \tan 2\theta = \frac{2\tan \theta}{1 - \tan^2 \theta} $$
- Half Angle Identities:
$$ \sin \frac{\theta}{2} = \pm \sqrt{\frac{1 - \cos \theta}{2}} $$
$$ \cos \frac{\theta}{2} = \pm \sqrt{\frac{1 + \cos \theta}{2}} $$
$$ \tan \frac{\theta}{2} = \pm \sqrt{\frac{1 - \cos \theta}{1 + \cos \theta}} = \frac{\sin \theta}{1 + \cos \theta} = \frac{1 - \cos \theta}{\sin \theta} $$
NoteThe sign of the half-angle identities depends on the quadrant in which $\frac{\theta}{2}$ lies.
Trigonometric Equations
Solving Basic Trigonometric Equations
To solve trigonometric equations, we often use identities and algebraic manipulation. Consider the equation:
$$ \sin x = \frac{1}{2} $$
The general solutions are:
$$ x = n\pi + (-1)^n \frac{\pi}{6}, \quad n \in \mathbb{Z} $$
Using Inverse Trigonometric Functions
Inverse trigonometric functions help in finding angles when the values of trigonometric functions are known. For example:
$$ \sin^{-1}(x), \cos^{-1}(x), \tan^{-1}(x) $$
If $\sin \theta = x$, then $\theta = \sin^{-1}(x)$.
ExampleSolve $\cos x = \frac{1}{2}$.
Using the inverse function:
$$ x = \cos^{-1} \left( \frac{1}{2} \right) $$
The principal value is:
$$ x = \frac{\pi}{3} $$
The general solutions are:
$$ x = 2n\pi \pm \frac{\pi}{3}, \quad n \in \mathbb{Z} $$
Conclusion
Trigonometric functions and equations are vital for mastering JEE Main Mathematics. Understanding the definitions, unit circle, identities, and methods to solve equations is crucial. Practice regularly with a variety of problems to gain confidence and proficiency.
TipRegularly revisit and practice trigonometric identities and equations. Use flashcards for quick revision of important angles and their trigonometric values.
Common MistakeA common mistake is to forget the periodic nature of trigonometric functions when solving equations, leading to missing solutions. Always check for all possible solutions within the given range.