Introduction
In the realm of physics, the concepts of work, power, and energy are fundamental to understanding the interactions and transformations that occur in physical systems. These concepts are interconnected and form the basis for analyzing various phenomena in mechanics and other areas of physics. This study note will delve into each of these concepts, providing a comprehensive understanding tailored for JEE Advanced Physics.
Work
Definition of Work
Work is defined as the transfer of energy that occurs when a force is applied to an object causing a displacement. The mathematical expression for work is:
$$ W = \vec{F} \cdot \vec{d} $$
where:
- $W$ is the work done,
- $\vec{F}$ is the force applied,
- $\vec{d}$ is the displacement of the object,
- $\cdot$ denotes the dot product.
Conditions for Work
For work to be done:
- A force must be applied.
- There must be displacement.
- The force must have a component in the direction of the displacement.
Work Done by a Constant Force
If the force is constant and the displacement is in a straight line, the work done can be simplified to:
$$ W = F \cdot d \cdot \cos(\theta) $$
where $\theta$ is the angle between the force vector and the displacement vector.
ExampleExample Calculation: A box is pushed with a force of 20 N across a floor for a distance of 5 meters. The force is applied at an angle of 30° to the horizontal. Calculate the work done.
$$ W = 20 , \text{N} \cdot 5 , \text{m} \cdot \cos(30^\circ) = 20 \cdot 5 \cdot \frac{\sqrt{3}}{2} = 50\sqrt{3} , \text{J} $$
Work Done by a Variable Force
When the force varies with position, the work done is given by the integral:
$$ W = \int_{x_i}^{x_f} F(x) , dx $$
NoteThis integral approach is crucial for understanding work done in non-uniform fields or when dealing with springs, where the force is a function of displacement.
Power
Definition of Power
Power is the rate at which work is done or energy is transferred. It is defined as:
$$ P = \frac{dW}{dt} $$
where:
- $P$ is the power,
- $dW$ is the infinitesimal work done,
- $dt$ is the infinitesimal time interval.
Average and Instantaneous Power
- Average Power over a time interval $\Delta t$ is: $$ P_{avg} = \frac{W}{\Delta t} $$
- Instantaneous Power is: $$ P = \vec{F} \cdot \vec{v} $$
where $\vec{v}$ is the instantaneous velocity.
ExampleExample Calculation: A car engine exerts a constant force of 4000 N to move the car at a constant speed of 20 m/s. Calculate the power output of the engine.
$$ P = F \cdot v = 4000 , \text{N} \cdot 20 , \text{m/s} = 80000 , \text{W} = 80 , \text{kW} $$
Energy
Definition of Energy
Energy is the capacity to do work. It exists in various forms such as kinetic energy, potential energy, thermal energy, etc.
Kinetic Energy
Kinetic energy is the energy possessed by an object due to its motion. It is given by:
$$ K.E. = \frac{1}{2} mv^2 $$
where:
- $m$ is the mass of the object,
- $v$ is its velocity.
Potential Energy
Potential energy is the energy possessed by an object due to its position or configuration. The most common forms are gravitational potential energy and elastic potential energy.
Gravitational Potential Energy
For an object of mass $m$ at a height $h$ in a uniform gravitational field:
$$ U = mgh $$
Elastic Potential Energy
For a spring with spring constant $k$ compressed or stretched by a distance $x$:
$$ U = \frac{1}{2} k x^2 $$
TipAlways remember to consider the reference point for potential energy. For gravitational potential energy, the reference point is usually taken at ground level where $h = 0$.
Conservation of Energy
The principle of conservation of energy states that energy cannot be created or destroyed, only transformed from one form to another. In an isolated system, the total energy remains constant:
$$ E_{total} = K.E. + P.E. = \text{constant} $$
Common MistakeA common mistake is to ignore non-conservative forces like friction when applying the conservation of energy principle. Always account for energy lost to non-conservative forces.
Work-Energy Theorem
The work-energy theorem links work and kinetic energy. It states that the work done by the net force on an object is equal to the change in its kinetic energy:
$$ W_{net} = \Delta K.E. = \frac{1}{2} mv_f^2 - \frac{1}{2} mv_i^2 $$
ExampleExample Calculation: A 2 kg object is initially at rest and is subjected to a net force that does 50 J of work on it. Calculate its final velocity.
Using the work-energy theorem:
$$ W_{net} = \Delta K.E. = \frac{1}{2} mv_f^2 - \frac{1}{2} mv_i^2 $$
Since the object is initially at rest, $v_i = 0$:
$$ 50 , \text{J} = \frac{1}{2} \cdot 2 , \text{kg} \cdot v_f^2 $$
Solving for $v_f$:
$$ v_f^2 = \frac{50 \cdot 2}{1} = 100 $$
$$ v_f = \sqrt{100} = 10 , \text{m/s} $$
Summary
Understanding work, power, and energy is crucial for analyzing mechanical systems in physics. These concepts are interrelated and provide a framework for solving a wide range of problems in mechanics. By mastering these principles, you will be well-equipped to tackle questions in JEE Advanced Physics.