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    Arianne plays a game of darts. The distance that her darts land from the centre, O, of the board can be modelled by a normal distribution with mean 10 cm and standard deviation 3 cm.

    Question
    HLPaper 2

    Arianne plays a game of darts. The distance that her darts land from the centre, O, of the board can be modelled by a normal distribution with mean 10 cm and standard deviation 3 cm.

    1.

    Find the probability that a dart lands less than 13 cm from O.

    [2]
    Verified
    Solution

    Let XXX be the random variable "distance from O ".

    X∼N(10,32)X \sim \mathrm{N}(10,3^2)X∼N(10,32)

    P(X<13)=0.841(0.841344…)\mathrm{P}(X<13)=0.841(0.841344 \ldots)P(X<13)=0.841(0.841344…)

    (M1)A1

    2.

    Find the probability that a dart lands more than 15 cm from O.

    [2]
    Verified
    Solution

    (P(X>15)=)0.0478(0.0477903)A1(\mathrm{P}(X>15)=) 0.0478(0.0477903) \quad \boldsymbol{A1}(P(X>15)=)0.0478(0.0477903)A1

    3.

    Each of Arianne's throws is independent of her previous throws. Find the probability that Arianne throws two consecutive darts that land more than 15 cm from O.

    [2]
    Verified
    Solution

    P(X>15)×P(X>15)\mathrm{P}(X>15) \times \mathrm{P}(X>15)P(X>15)×P(X>15) (M1) =0.00228(0.00228391…)=0.00228(0.00228391 \ldots)=0.00228(0.00228391…) A1

    4.

    In a competition a player has three darts to throw on each turn. A point is scored if a player throws all three darts to land within a central area around O. When Arianne throws a dart the probability that it lands within this area is 0.8143. Find the probability that Arianne does not score a point on a turn of three darts.

    [2]
    Verified
    Solution

    1−(0.8143)31-(0.8143)^{3}1−(0.8143)3 M1A1

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    5.

    In the competition Arianne has ten turns, each with three darts. Find Arianne's expected score in the competition.

    [2]
    Verified
    Solution

    let YYY be the random variable "number of points scored" evidence of use of binomial distribution (M1) (E(Y)=)10×0.539949…(\mathrm{E}(Y)=) 10 \times 0.539949 \ldots(E(Y)=)10×0.539949… =5.40=5.40=5.40 A1

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    6.

    Find the probability that Arianne scores at least 5 points in the competition.

    [3]
    Verified
    Solution

    (P(Y≥5)=)0.717(0.716650…)(\mathrm{P}(Y \geq 5)=) 0.717(0.716650 \ldots)(P(Y≥5)=)0.717(0.716650…)

    A1

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    7.

    Find the probability that Arianne scores at least 5 points and less than 8 points.

    [2]
    Verified
    Solution

    P(5≤Y<8)\mathrm{P}(5 \leq Y<8)P(5≤Y<8) (M1) =0.628(0.627788…)=0.628(0.627788 \ldots)=0.628(0.627788…) A1 Note: Award M1\boldsymbol{M1}M1 for a correct probability statement or indication of correct lower and upper bounds, 5 and 7.

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    8.

    Given that Arianne scores at least 5 points, find the probability that Arianne scores less than 8 points.

    [2]
    Verified
    Solution

    P(5≤Y<8)P(Y≥5)(=0.627788…0.716650…)\frac{\mathrm{P}(5 \leq Y<8)}{\mathrm{P}(Y \geq 5)}\left(=\frac{0.627788 \ldots}{0.716650 \ldots}\right)P(Y≥5)P(5≤Y<8)​(=0.716650…0.627788…​) (M1) =0.876(0.876003…)=0.876(0.876003 \ldots)=0.876(0.876003…) A1

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